This shows that it will take the particle 23 secs to meet.
The distance travelled by each particle is 50cm
If two particles are projected simultaneously towards each other from opposite ends of a straight horizontal tube,
The first particle distances are 97cm, 93cm, 89cm... every 2secs
This form an arithmetic sequence and the nth term is expressed as:
Tn = a + (n - 1)d
a is the first term = 97
d is the common difference = 4
Substitute
Tn = 97+(n - 1)(4)
Tn = 97 + 4n -4
Tn = 4n + 93
Similarly for the distances 49 cm, 47 cm, 45cm .....
This also forms an arithmetic sequence and the nth term is expressed as:
Tn = a + (n - 1)d
a is the first term = 49
d is the common difference = 2
Substitute
Tn = 49+(n - 1)(2)
Tn = 49 + 2n -2
Tn = 2n + 47
For the particles to meet, this means that 4n + 93 = 2n + 47
4n - 2n = 47 - 93
2n = -46
n = -23
This shows that it will take the particle 23 secs to meet.
To get the distance travelled by each particle
Tn = 4n + 93
T2 = 4(2) + 93
T2 = 101
For the other sequence;
Tn = 2n + 47
T2 = 2(2) + 47
T2 = 51
Taking the difference;
D = 101 - 51 = 50cm
Hence the distance travelled by each particle is 50cm
Learn more here: brainly.com/question/13989292
