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konstantin123 [22]
3 years ago
12

PLEASE HELP! An organization surveyed a random sample of their employees about their new vacation policy. Out of the employees s

urveyed, 83% rated the vacation policy as "delightful" with a margin of error of ±2% and a confidence interval of 95%.
What does the margin of error imply?

A.It can be concluded, with 81% confidence, that between 93% and 97% of all employees will rate the vacation policy as "delightful."

B.It can be concluded, with 95% confidence, that at least 81% of all employees will rate the vacation policy as "delightful."

C.It can be concluded, with 95% confidence, that between 81% and 85% of all employees will rate the vacation policy as "delightful."

D.It can be concluded, with 81% confidence, that at least 95% of all employees will rate the vacation policy as "delightful."
Mathematics
2 answers:
KengaRu [80]3 years ago
8 0
The answer is C.

<span>Let me know if you have any other questions! ♥</span>
dexar [7]3 years ago
4 0

Answer:

The answer is option C.

Step-by-step explanation:

Here, according to the given question, margin of error means that the number of people who rated the vacation as 'delightful' ranges between 81% (83-2) and 85% (83+2) of the population at a 95% confidence interval. The range is formed as 81% to 85% as its given that the margin of error is ±2% .

<em>Therefore, only option C is having both the ranges, 81% and 85%. So, option C is the correct answer.</em>

C.It can be concluded, with 95% confidence, that between 81% and 85% of all employees will rate the vacation policy as "delightful."

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The answer is -220 
What you do is take -7 and multiply that by (1+2+3+4+5+6+7+8+9+10+11) and then after that add 11 again and multiply it by 22. It would look like this. 

-7 x (1+2+3+4+5+6+7+8+9+10+11) +11 x 22

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━━━━━━━☆☆━━━━━━━

▹ Answer

<em>b = -11</em>

▹ Step-by-Step Explanation

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Hope this helps!

- CloutAnswers ❁

Brainliest is greatly appreciated!

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7 0
4 years ago
Read 2 more answers
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