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3 years ago

What’s the reciprical of 5/6 divided by 15

Mathematics

1 answer:

Oliga [24]3 years ago

7 0

Answer:

18/1 (18)

The drawing will help

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<img src="https://tex.z-dn.net/?f=%20-%2030%20%3D%202%28x%20-%2097%29" id="TexFormula1" title=" - 30 = 2(x - 97)" alt=" - 30 = 2

Korolek [52]

Hey there!

In order to find out the answer to this question, we can distribute

$-30 = 2(x - 97) \\ \\ \\ 2(x) = 2x \\ \\ 2(97) = 197$

Flip your problem around!

$2x - 194 = -30$

Add by $194$ on each of your sides

Like: $2x - 194 + 194 \\ \\ \\ -30 + 194$

Cancel out: $-194 + 194$ because they would give you the outcome of $0$

Keep: $-30 + 194 [/tex] because that'll give you: [tex]164$

Your problem becomes: $2x = 164$

Now, we have to divide by $2$ on each of the sides

Like: $\frac{2x}{2} = \frac{164}{2}$

Cancel: $\frac{2x}{2}$ because it will give you a outcome of $1$

Keep: $\frac{164}{2}$ because this will give you your answer

$Answer: x = 82$

Good luck on your assignment and enjoy your day!

~ $LoveYourselfFirst:)$

7 0

3 years ago

Multiple choice please answer please

eduard

Answer: 33.85 mm

Step-by-step explanation:

Use trigonometry, tan equation

You are give the tan angle and adjacent side, you need to find the opposite side so

T A

Tan(72)= x/11

x= tan(72) x 11

x= 33.85

8 0

3 years ago

Read 2 more answers

X3 - 3x^2- 54x + 112

Olegator [25]

Answer:

(x -2) (x- 8) (x+7)

Step-by-step explanation:

6 0

2 years ago

Mrs. Del Pup bought 20 yards of border for her classroom bulletin board.

KengaRu [80]

A rectangle with dimensions $x$ and $y$ has perimeter 20 if

$2(x+y)=20 \iff x+y=10$

and we can deduce

$y=10-x$

So, the dimensions of the rectangle must be $x$ and $10-x$ , where x ranges from 0 to 10 (both extremes are excluded, otherwise you'd have a degenerate rectangle, which is actually a segment).

So, all the possible areas are given by the product of the dimensions, i.e.

$x(10-x) = -x^2+10x$

The function $f(x)=-x^2+10x$ represents a parabola, facing downwards, and thus it admits a maximum, which is its vertex.

In particular, the vertex of this parabola is given by

$x=\dfrac{-b}{2a}=\dfrac{-10}{-2}=5$

And it yields an area of

$f(5)=-25+50=25$

(a) So, she can frame a maximum area of 25 squared yards.

(b)The dimensions of the rectangle with greatest area are $x=5$ and $y=10-x=10-5=5$ , so it's actually a square.

This is a well known theorem: if you fix the perimeter, the rectangle with the largest area is the square yielding that perimeter.

(c) If we increase both dimensions by 2 yards, our 5x5 square would become a 7x7 square...

(d) ...and the new area would be $7^2=49$ squared yards. So, the new area is $49-25=26$ squared yeards more than the old one.

6 0

3 years ago

F(n+1)=f(n)-8. If f(1)=100,what Is f(6)

Tanya [424]

I think it is f(6)= 39

6 0

3 years ago