The point y (-3,-1) is rotates 270 degrees. Please help

Mathematics

1 answer:

uranmaximum [27]3 years ago

6 0

it is going to be c cause i know cause my kid does it

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Rasek [7]

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3 years ago

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sergeinik [125]

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3 years ago

The points A(1, 4), B(5,1) lie on a circle. The line segment AB is a chord. Find the equation of a diameter of the circle.

tangare [24]

Check the picture below.

well, we want only the equation of the diametrical line, now, the diameter can touch the chord at any several angles, as well at a right-angle.

bearing in mind that <u>perpendicular lines have negative reciprocal</u> slopes, hmm let's find firstly the slope of AB, and the negative reciprocal of that will be the slope of the diameter, that is passing through the midpoint of AB.

$\bf A(\stackrel{x_1}{1}~,~\stackrel{y_1}{4})\qquad B(\stackrel{x_2}{5}~,~\stackrel{y_2}{1}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{1}-\stackrel{y1}{4}}}{\underset{run} {\underset{x_2}{5}-\underset{x_1}{1}}}\implies \cfrac{-3}{4} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{slope of AB}}{-\cfrac{3}{4}}\qquad \qquad \qquad \stackrel{\textit{\underline{negative reciprocal} and slope of the diameter}}{\cfrac{4}{3}}$

so, it passes through the midpoint of AB,

$\bf ~~~~~~~~~~~~\textit{middle point of 2 points } \\\\ A(\stackrel{x_1}{1}~,~\stackrel{y_1}{4})\qquad B(\stackrel{x_2}{5}~,~\stackrel{y_2}{1}) \qquad \left(\cfrac{ x_2 + x_1}{2}~~~ ,~~~ \cfrac{ y_2 + y_1}{2} \right) \\\\\\ \left( \cfrac{5+1}{2}~~,~~\cfrac{1+4}{2} \right)\implies \left(3~~,~~\cfrac{5}{2} \right)$

so, we're really looking for the equation of a line whose slope is 4/3 and runs through (3 , 5/2)

$\bf (\stackrel{x_1}{3}~,~\stackrel{y_1}{\frac{5}{2}}) \stackrel{slope}{m}\implies \cfrac{4}{3} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{\cfrac{5}{2}}=\stackrel{m}{\cfrac{4}{3}}(x-\stackrel{x_1}{3})\implies y-\cfrac{5}{2}=\cfrac{4}{3}x-4 \\\\\\ y=\cfrac{4}{3}x-4+\cfrac{5}{2}\implies y=\cfrac{4}{3}x-\cfrac{3}{2}$

4 0

3 years ago

202 divided by 3 with a remaining number

svlad2 [7]

Answer:

$67 R \frac{1}{3}$

I hope this helps!

7 0

3 years ago

Read 2 more answers

what is the equation of the line that passes through (-2,-3) and is perpendicular to 2x-3y=6? ...?

sergij07 [2.7K]

The equation given in the question is

2x - 3y = 6
Dividing both sides of the equation by 3, we get
2/3 x - y = 2
y = 2/3 x - 2
Then, from the above equation we can tell that the slope of the line in the graph is 2/3. The slope of a line perpendicular to this slope will be - 3/2. The line also contains the points (-2,-3).
Then, the equation of the perpendicular line will be
y = mx + b
- 3 = (- 3/2)(- 2) + b
- 3 = 3 + b
b = - 6
Then
y = (-3/2)x - 6
y + 6 = (- 3/2)x
2y + 12 = - 3x
3x + 2y = - 12

4 0

3 years ago