here we have 3X to 5 seventh power in radical form
we need write this in radical form we knwo that 
so ![3x^{5/7} =\sqrt[7]{3x^{5}}](https://tex.z-dn.net/?f=%203x%5E%7B5%2F7%7D%20%3D%5Csqrt%5B7%5D%7B3x%5E%7B5%7D%7D%20%20%20)
this will be the radical form .
1501 / 200
this is what i looked up an got
X = y2 is the equation for it just plug in the numbers
Let us start subtracting 3 cos theta both sides so that we may get all theta terms on left side only
It is now : 4 cos theta - 3 cos theta = - (sqrt3)/ 2
1 cos theta = -( sqrt 3 ) /2
we know cos (pi-x)= - cos x And cos (pi+ x)= - cos (x)
********* let us first use :
- Cos ( pi - theta) = - ( sqrt 3 )/2
this implies cos (pi- theta )= (sqrt 3) /2
cos ( pi - theta )= cos (pi /6)
pi- theta = pi/6
pi- pi/6 = theta
5 pi/6 = theta
one of teh answer is 5 pi/6 . another value of theta would be :
(2pi - 5pi/6)= 7pi/6
Answer: 5 pi/6 and 7 pi/6
Answer:
Area of the triangle is 10 square units
Step-by-step explanation:
Recall that the formula for the area of a triangle is: "base x height / 2", and in this case, we can consider the triangle's base as the segment that joins the vertices (5, 4) and (5, 8) which gives a segment length of 4 units. The height of the triangle is then the distance between the third vertex (0,7) and the base, which is exactly 5 units. Then the area becomes:
Area = 4 x 5 / 2 = 10 square units.
