Question

X/-2=4, X/3+13=13, Z/2+2=4 plz show ur work and explain how u did it

Answer 1

$\dfrac{x}{-2}=4\ \ \ |multiply\ both\ sides\ by\ (-2)\\\\(-2)\cdot\dfrac{x}{-2}=(-2)\cdot4\\\\\boxed{x=-8}\\\\\dfrac{x}{3}+13=13\ \ \ |subtract\ 13\ from\ both\ sides\\\\\dfrac{x}{3}+13-13=13-13\\\\\dfrac{x}{3}=0\ \ \ |multpily\ both\ sides\ by\ 3\\\\\not3^1\cdot\dfrac{x}{\not3_1}=0\\\\\boxed{x=0}$

$\dfrac{z}{2}+2=4\ \ \ |subtract\ 2\ from\ both\ sides\\\\\dfrac{z}{2}+2-2=4-2\\\\\dfrac{z}{2}=2\ \ \ \ |multiply\ both\ sides\ by\ 2\\\\\not2^1\cdot\dfrac{z}{\not2_1}=2\cdot2\\\\\boxed{z=4}$