Answer:
A' (-3,7)
B' (0,10)
C' (12,10)
D' (-2,-4)
Step-by-step explanation:
A' (-6+3 , 3+4) = (-3,7)
B' (-3+3 , 6+4) = (0,10)
C' (9+3 , 6+4) = (12,10)
D' (-5+3 , -8+4) = (-2,-4)
Solution
For this case we need to find the number of cubes in the stack given so then we can do this:
The first line present 5 cubes
The second line present 5 cubes
And the last line we got:
10 cubes
Then the total of cubes are:
10 +5+5 = 20 cubes
If we need to find the number of faces we can do the following:
5+ 4+ 4+4 +4 +1 + (5+4+4+4+4+1 ) + (5+4+4+4+4+1 ) + (5+ 4+4+4 +4 )
And solving we got:
22+22+ 22+21= 87
Let one integer be x, the consecutive odd integer is x+2
reciprocals are 1/x and 1/(x+2)
1/x +1/(x+2)=24/143
make the denominators the same:
(x+2)/[x(x+2)] +x/[x(x+2)]=24/143
143(2x+2)=24(x)(x+2)
286x+286=24x²+48x
24x²-238x-286=0
use the quadratic formula: x=22 this doesn't work because 22 is not an odd number.
or x=-2.1666666666 (this is not an integer)
weird.
Answer:
9600
Step-by-step explanation:
y varies inversely with the square of x
y=k/(x^2)
for some non-zero constant k
y=6 when x=4
6=k/(4^2)
k=96
y=96/(x^2)
x=0.1
y=96/(0.1^2)
y=9600
Answer:
Step-by-step explanation:
