Answer:
The ball will be 84 feet above the ground 1.125 seconds and 4.5 seconds after launch.
Step-by-step explanation:
Statement is incorrect. Correct form is presented below:
<em>The height </em>
<em> of an ball that is thrown straight upward from an initial position 3 feet off the ground with initial velocity of 90 feet per second is given by equation </em>
<em>, where </em>
<em> is time in seconds. After how many seconds will the ball be 84 feet above the ground. </em>
We equalize the kinematic formula to 84 feet and solve the resulting second-order polynomial by Quadratic Formula to determine the instants associated with such height:
(1)
By Quadratic Formula:
, 
The ball will be 84 feet above the ground 1.125 seconds and 4.5 seconds after launch.
Answer:
Infinitely many solutions.
Step-by-step explanation:
In the equation −2y + 2y + 3 = 3 we see only one variable, and that variable is of the first power. Ordinarily, we'd say that this equation will have 1 solution. However, if we combine like terms, we get 0 + 3 = 3, or 0 = 0, which is true for any and all y values. Infinitely many solutions.
Answer:
prime numbers are the natural numbers greater than one that are not products of two smaller natural numbers
Step-by-step explanation:
Answer:
$3200
Step-by-step explanation:
1000x40x8/100
pls make me brainlist
You have to include a drawing that relates the distace between de towers and some angles.
I will use one that gives the angle from the base of Seafirst Tower to the top of Columbia tower as 53 degress.
This lets you calculate the distance between the towers, d, as
tan(53) = 954 / d => d = 954 / tan(53) = 718.89ft
The same drawing gives the angle from the the base of the Columbtia tower to the top of the Seafirst Tower as 27 degrees.
Tnen, tan(27) = height / d => height = d*tan(27) = 718.89*tan(27) = 366.29 ft
Answer: 366.29 ft
