the table below:
Grade In favor Opposed Undecided Total
Grade 9 6 4 8 18
Grade 10 10 11 9 30
Grade 11 12 15 11 38
Grade 12 15 6 14 35
If the principal randomly selects a student in grade 10 from this survey,
the probability that the student is opposed to extending the school day
P ( student in grade 10 is opposed)= Number of student in opposed(grade10) / total number of students in grade 10
Number of student opposed who is in grade10 = 11
total number of students in grade 10 = 30
P( student in grade 10 is opposed)=
= 0.37
the probability that the student is opposed to extending the school day= 0.37
Answer:
Step-by-step explanation:
Given
See attachment
Solving (a):
To solve for , we make use of:
The relationship between both angles is that they are complementary angles
Make the subject
Substitute for
Solving (b):
To solve for , we make use of:
The relationship between both angles is that they are complementary angles
Solving (c):
To solve for , we make use of:
The relationship between both angles is that they are alternate exterior angles.
So:
Answer:
sinA = h/c; sinC = h/a
Step-by-step explanation:
Which pair of equations below is a result of constructing the altitude, h, in Triangle ABC?
sinA= h/c
sinC= h/a
sinA= h/c
sinB= b/c
sinA= b/c
sinC= b/a
Solution:
A triangle is a polygon with three sides and three angles. There are different types of triangles such as right angled, acute, obtuse and isosceles triangle.
In right angle triangle, one angle is 90°. From Pythagoras theorem, the square of the longest side (hypotenuse) is equal to the sum of the square of the two sides.
In right triangle, trigonometric identities are used to show the relationship between the sides of a triangle and the angles.
sinθ = opposite / hypotenuse, cosθ = adjacent / hypotenuse, tanθ = opposite / adjacent
Therefore in triangle ABC:
sinA = h/c; sinC = h/a
Answer:
x = -1 or 2
Step-by-step explanation:
Taking the antilog, you have the quadratic ...
x^2 -x -1 = 1
x^2 -x -2 = 0 . . . . subtract 1
(x -2)(x +1) = 0 . . . factor
The values of x that make these factors zero are the solutions to the equation.
x = 2 or x = -1
