Which pair of equations below is a result of constructing the altitude, h, in traingle ABC?
1 answer:
Answer:
sinA = h/c; sinC = h/a
Step-by-step explanation:
Which pair of equations below is a result of constructing the altitude, h, in Triangle ABC?
sinA= h/c
sinC= h/a
sinA= h/c
sinB= b/c
sinA= b/c
sinC= b/a
Solution:
A triangle is a polygon with three sides and three angles. There are different types of triangles such as right angled, acute, obtuse and isosceles triangle.
In right angle triangle, one angle is 90°. From Pythagoras theorem, the square of the longest side (hypotenuse) is equal to the sum of the square of the two sides.
In right triangle, trigonometric identities are used to show the relationship between the sides of a triangle and the angles.
sinθ = opposite / hypotenuse, cosθ = adjacent / hypotenuse, tanθ = opposite / adjacent
Therefore in triangle ABC:
sinA = h/c; sinC = h/a
You might be interested in
First step of a synthetic divison is that we need to carry down the leading coefficient. Here the leading coefficient is 2. So, carry down 2 at the bottom.
Next step is to multiply the divisor -3 with this carry down number 2. So, we have got 3*(-2)= -6 which will place atthe bottom of the next coefficient 4.
Next step is to add this column.
Now repeat the same method again till the last colum.
At the end we have got 0 after the addition. Which means the remainder is 0.
So, the quotient is 2x^2-2x+2.
