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3 years ago

Jessica's credit card is on a 30-day billing cycle, and it computes finance charges using the adjusted balance method. The

2 answers:

7 0

I’m confused it says 131.796 and also 1,240,55. So idk which one’s are even correct. If you try asking the question again I can give you the answer

Helga [31]3 years ago

3 0

Answer:

B.) $1,033.76

Step-by-step explanation:

You might be interested in

Maria is comparing the prices of two window cleaning companies. Company A charges $6 per window and an additional $12 as service

bija089 [108]

Part A
y=6x+12
y=5x+15
x is the amount of windows, y is the total amount of money
Part B
y=6(8)+12 =60
y=5(8)+15 =52
Company B
Part C
y=6(6)+12 =48
y=5(6)+12 =42
$6 is saved

4 0

3 years ago

to get ready for a field trip, students and adults were put into groups. for every 8 students in a group , there were 3 adults.

Vladimir [108]

There were 18 adults on the field trip. See, since 8x6=48, and there are 3 adults in each group, and there are 6 groups, there are 18 adults (6x3=18)

4 0

4 years ago

How do you do this question?

AfilCa [17]

<h3>4 Answers: A, B, C, D</h3>

=======================================================

Explanation:

f(x) is continuous when x >= 1. The only discontinuity for f(x) is when x = 0, but 0 is not part of this interval.

f(x) is positive for any valid x value in the domain since x^6 is always positive. In general, x^n is positive for all x when n is any even number.

f(x) is decreasing. You can see this through a table of values or through a graph. For anything in the form 1/(x^k), it will be a decreasing function because x^k gets larger, so 1/(x^k) gets smaller, when x goes to infinity.

--------------------

The conditions to use the integral test have been met. So we have to see if $\displaystyle \int_1^{\infty}f(x)dx$ converges or not.

Let's integrate and find out

$\displaystyle \int \frac{1}{x^6} dx = \int x^{-6} dx\\\\\\ \displaystyle \int \frac{1}{x^6} dx = \frac{1}{1+(-6)}x^{-6+1}+C\\\\\\ \displaystyle \int \frac{1}{x^6} dx = \frac{1}{-5}x^{-5}+C\\\\\\ \displaystyle \int \frac{1}{x^6} dx = -\frac{1}{5}*\frac{1}{x^5}+C\\\\\\ \displaystyle \int \frac{1}{x^6} dx = -\frac{1}{5x^5}+C\\\\$

So we have

$\displaystyle g(x) = \int f(x) dx\\\\\\\displaystyle g(x) = \int \frac{1}{x^6} dx\\\\\\\displaystyle g(x) = -\frac{1}{5x^5}+C\\\\\\$

Meaning that,

$\displaystyle \int_{a}^{b} f(x) dx = g(b)-g(a)\\\\\\\displaystyle \int_{a}^{b} \frac{1}{x^6} dx = \left(-\frac{1}{5b^5}+C\right)-\left(-\frac{1}{5a^5}+C\right)\\\\\\\displaystyle \int_{a}^{b} \frac{1}{x^6} dx = -\frac{1}{5b^5}+\frac{1}{5a^5}\\\\\\$

If we plug in a = 1 and apply the limit as b approaches positive infinity, then the expression $-\frac{1}{5b^5}+\frac{1}{5a^5}$ will turn into $\frac{1}{5}$

Therefore,

$\displaystyle \int_{1}^{\infty} \frac{1}{x^6} dx = \frac{1}{5}\\\\\\$

Because this integral converges, this means the series $\displaystyle \sum_{n=1}^{\infty}\frac{1}{n^6}$ also converges as well by the integral test.

7 0

3 years ago

Select the correct answer

Tomtit [17]

Answer:

Step-by-step explanation:

The area for a triangle is

$A=\frac{1}{2}bh$

Our base is given as x, the height is given as 1 more than 6 times the base which looks like this: 6x + 1. We know that the area is 13, so filling in everything:

$13=\frac{1}{2} (6x+1)(x)$