Question

When purchased, a plastic beach ball is deflated and packaged flat. The package states that when inflated to its maximum capacity, the radius of the inflated ball is 6.5 inches. To the nearest cubic inch, how much air will occupy the space contained by the inflated beach ball? Use 3.14 to approximate . In your final answer, include your calculations.

Answer 1

V=43πr3=43·π·6.53≈1150.34651   or  rounded 1150.35

Answer 2

Answer: 1150 cubic inches

Step-by-step explanation:

The volume of sphere is given by :-

$\text{Volume}=\frac{4}{3}\pi r^3$, where r is the radius of sphere.

Given: The radius of the inflated ball = 6.5 inches.

Then, the volume of inflated ball will be :-

$\text{Volume of inflated ball}=\frac{4}{3}\pi (6.5)^3\\\\\Rightarrow\text{Volume of inflated ball}=\frac{4}{3}(3.14)(274.625) \\\\\Rightarrow\text{Volume of inflated ball}=1149.76333333\approx1150\ in.^3$

Hence, air will occupy the 1150 cubic inches space contained by the inflated beach ball