Answer:
a) distance covered by hare d1 = 8t
b) distance covered by tortoise d2 = 5t + 550
c) ∆d = 550 - 3t
Step-by-step explanation:
Given;
Speed of hare u = 8m/s
Speed of tortoise v = 5 m/s
Initial distance of tortoise d0 = 550 m
a) using the equation of motion;
distance covered = speed × time + initial distance
d = vt + d0
For hare;
d0 = 0
Substituting the values;
d1 = 8t + 0
d1 = 8t
b)using the equation of motion;
distance covered = speed × time + initial distance
d2 = vt + d0
For tortoise;
d0 = 550m
Substituting the values;
d2 = 5t + 550
d2 = 5t + 550 m
c) the number of meters the tortoise is ahead of the hare.
∆d = distance covered by tortoise - distance covered by hare
∆d = d2 - d1
Substituting the values;
∆d = (5t + 550) - 8t
∆d = 550 - 3t
Answer:
The perpendicular line is:
y = 1/3 x + 2/3
Step-by-step explanation:
The given equation can be reduced to its slope-intercept form as shown below:
3x + 9y = 8y - 2
subtract 8 y from both sides
3 x + y = -2
subtract 3 x from both sides
y = - 3 x -2
therefore we know that the slope of this line is -3, and then, a perpendicular line to it must have slope given by the "opposite of the reciprocal" of this slope. That is, the slope of any perpendicular line to this one must be: 1/3
We use this slope to find the equation of the line passing through the point (13. 5)
y = 1/3 x + b
passing through (13, 5) means:
5 = 1/3 (13) + b
therefore, we can find b from the above equation
b = 5 - 13/3 = 15/3 - 13/3 = 2/3
Then the equation of this perpendicular line is:
y = 1/3 x + 2/3
First, you need no find out how much is 45% of 15,00. ( it is $6,750)
so then you need to multiply that number by 2
them you get $13,500
so his parents saved up $13,500
840,00 is a reasonable rounding
