Answer:
pls you did not give us the statements
The correct answer is 127.
:)
Answer:
Step-by-step explanation:
Assuming the rate of increase in the cost of tuition fee per year is linear. We would apply the formula for determining the nth term of an arithmetic sequence which is expressed as
Tn = a + (n - 1)d
Where
a represents the first term of the sequence.
d represents the common difference.
n represents the number of terms in the sequence.
From the information given,
a = $20500(amount in 2000)
From 2000 to 2018, the number of terms is 19, hence,
n = 19
T19 = 454120
Therefore,
454120 = 20500 + (19 - 1)d
454120 - 20500 = 18d
18d = 433620
d = 433620/18
d = 24090
Therefore, the equation that can be used to find the tuition y for x years after 2000 is expressed as
y = 20500 + 24090(x - 1)
To to estimate the tuition at this college in 2020, the number of terms between 2000 and 2020 is 21, hence
x = 21
y = 20500 + 24090(21 - 1)
y = 20500 + 481800
y = $502300
Let the oranges cost = x
Let the apples cost = y
According to given conditions, equation becomes:
.... (1)
.....(2)
Multiplying equation (1) by 8 and equation (2) by 12 to get y
96x+48y=43.04 .... (3)
96x+60y=44.16 .... (4)
Now subtracting both equations we get,
12y = 1.12
y = 0.093
Hence, cost of 1 apple = $0.093
As 12x+6y=5.38
12x+6(0.093)=5.38
12x=4.822
x = 0.40
Hence, cost of 1 orange = $0.40
