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PolarNik [594]
2 years ago
13

Question:

Mathematics
1 answer:
Archy [21]2 years ago
5 0

The construction goes with P and set its width to M.

The correct option is (A).

<h3>What is perpendicular bisector ?</h3>

A perpendicular bisector of a line segment is a line segment perpendicular to and passing through the midpoint of  figure.

Now, a line perpendicular to AB and passing through an external point M.

first step :Put the compass needle on M and, keep the compass width the same then draw two arcs that intersect AB.

Second step: After drawing arcs, from the intersecting points named P and Q.

Now, keeping the width of compass same as before and to the opposite side of M draw an arc named it as M'

Third step: Using straightedge draw line passes through M.

The lines which passes through M will be perpendicular to AB.

The above discussed are steps to draw perpendicular bisector of AB.

Learn more about this concept here:

brainly.com/question/16826334

#SPJ1

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A.0.5×10^4
Juliette [100K]

Answer:

sdd

Step-by-step explanation:

3 0
3 years ago
What is the domain of the set (-3,5), (2,0), (7,-5)​
Valentin [98]

The domain is all x-values.

The domain is -3, 2, 7

The range is all y-values

The range is 5, 0, -5

Best of Luck!

4 0
3 years ago
Solve for f (-3) for f (x) = 1 -x<br> f (-3) = [ ? ]
Lostsunrise [7]
F(x) = 1 - x
f(-3) = 1 - (-3)
f(-3) = 4
3 0
3 years ago
Read 2 more answers
Please help me, this is PEDMAS
rusak2 [61]

Answer:

1). 183

2). 83

3). 353

4). -2652

5). 59

6). 510

7). -293

8). 79

9). 78

10). 87

Step-by-step explanation:

Considering order of operation, parenthesis must be simplified first.

The solutions to the given questions are shown below;

1). \ \ 5+(7\times (3+2)^2) + 3=8 +  (7\times (5)^2)  = 8 + (7\times 25) = 8 + 175 = 183

2). \ 16+(8+ (6+2)^2) - 5=16-5 +  (8+ (8)^2)  = 11 + (8+64) = 11 + 72 = 83

3). \ (15+ 3)^2 + ((14+6)+3^2)= (18)^2 + ((20) + 9) = 324 + (29) = 353

4). \ ((11+ 2)-(24+2)^2)\times 2^2 = (13 - 676) \times 4  = (-663)\times 4 = -2652

5). \ ((4+3)^2+ 6) -5+3^2= (49 + 6) - 5 + 9= (49+6+9) - 5 = 64-5 = 59

6). \ (20+ 2)^2 +((15+7)+2^2)= (484) + (22+ 4)= 484 + 26 =510

7). \ ((12 + 4)- (15+3)^2+ 5^2 = (16 -  324) + 25 = -318 + 25 = -293

8). \ (6^2+ (24+ 3+5^2)) - 3^2= (36 + (52)) - 9 = (88) - 9 = 79

9). \ ((10-4)^2\times 2) + 2 + 2^2= ((6)^2 \times 2) + 2 + 4 = (36\times 2)+ 6 = 72 + 6 = 78

10). \ (7^2 + (16 + 8 + 2^2)) + 3^2 = (49 + 28) + 9 = 78 + 9 = 87

3 0
3 years ago
for the opening day of a carnival, 800 admission tickets were sold. The receipts totaled $3775. Tickets for children cost $3 eac
zloy xaker [14]
Total tickets sold  = 800
Total revenue = $3775

Ticket costs:
$3  per child,
$8  per adult,
$5 per senior citizen.

Of those who bought tickets, let
x =  number of children 
y = number of adults
z = senior citizens

Therefore
x + y + z = 800                   (1)
3x + 8y + 5z = 3775           (2)

Twice as many children's tickets were sold as adults. Therefore
x = 2y                                (3)

Substitute (3) into (1) and (2).
2y + y + z = 800, or
3y + z = 800, or
z = 800 - 3y                        (4)
3(2y) + 8y + 5z = 3775, or
14y + 5z = 3775                 (5)

Substtute (4) nto (5).
14y + 5(800 - 3y) = 3775
-y = -225
y = 225
From (4), obtain
z = 800 - 3y = 125
From (3), obtain
x = 2y = 450

Answer:
The number of tickets sold was:
450 children,
225  adults,
125 senior citizens.
6 0
4 years ago
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