B=7
3(b-4)+5b=44
3b-12+5b=44
8b=44+12
8b=56
b=7
Answer:
The equation for difference in altitude of the two helicopters is A = 650 - 100t
Step-by-step explanation:
Given;
The altitude of one helicopter is, A1 = 600 + 150t
The altitude of a second helicopter is, A2 = 1250 + 50t
Their difference in altitude, A at time t, is calculated as
A₂ - A₁ = A = (1250 + 50t) - (600 + 150t)
A₂ - A₁ = A = 1250 + 50t - 600 -150t
A₂ - A₁ = A = 1250 - 600 + 50t - 150t
A₂ - A₁ = A = 650 - 100t
Therefore, the equation for difference in altitude of the two helicopters is A = 650 - 100t
Idk I Would Fine The Answer To Your Question Now
-2x - 4 > 8...add 4 to both sides
-2x > 8 + 4
-2x > 12...divide both sides by -2 and change inequality sign
x < 12/-2
x < -6
Hey there! Your answer is:
1,963
Step-by-step explanation:
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