the number of elements in the union of the A sets is:5(30)−rAwhere r is the number of repeats.Likewise the number of elements in the B sets is:3n−rB
Each element in the union (in S) is repeated 10 times in A, which means if x was the real number of elements in A (not counting repeats) then 9 out of those 10 should be thrown away, or 9x. Likewise on the B side, 8x of those elements should be thrown away. so now we have:150−9x=3n−8x⟺150−x=3n⟺50−x3=n
Now, to figure out what x is, we need to use the fact that the union of a group of sets contains every member of each set. if every element in S is repeated 10 times, that means every element in the union of the A's is repeated 10 times. This means that:150 /10=15is the number of elements in the the A's without repeats counted (same for the Bs as well).So now we have:50−15 /3=n⟺n=45
Answer:
Answers are below
Step-by-step explanation:
5+1=6 No
78+6=76+8 Yes, commutative property of addition
2x+(3x+4x)=(2x+3x)+4x Yes, associative property of addition
52+(-18)=(-52)+18 No
6+(-6)=0 Yes, identity property of addition
If these answers are correct, please make me Brainliest!
-37m = 12
plug in the numbers:
(-28)(-37) ≠ 12
(-26)(-37)≠12
(26)(-37)≠12
(28)(-37) ≠ 12
idk none of the given answers are correct. Sorry.
Answer:
m∠A = 31
b = 13.3
Step-by-step explanation:
Answer:
7m² - 5m + 8 + 3/(m+3)
Step-by-step explanation:
7m³+16m²-7m+27
(7m³+21m²-5m²-15m+8m+24+3)/(m+3)
[7m²(m+3) - 5m(m+3) + 8(m+3) + 3]/(m+3)
7m² - 5m + 8 + 3/(m+3)
