Answer:
Dosage= 500 mg
Frequency= twice a day (every 12 hours)
Duration= 10 days
Number of dosage= 10*2= 20
residual drug amount after each dosage= 4.5%
We can build an equation to calculate residual drug amount:
- d= 500*(4.5/100)*t= 22.5t, where d- is residual drug, t is number of dosage
- After first dose residual drug amount is:
d= 500*0.045= 22.5 mg
- After second dose:
d= 22.5*2= 45 mg
As per the equation, the higher the t, the greater the residual drug amount in the body.
Maximum drug will be in the body:
- d= 20*22.5= 450 mg at the end of 10 days
Maximum drug will be in the body right after the last dose, when the amount will be:
Tenth:44.600
What is in the tenths place? The 5.
What is to the right of it?
The 8
Since the 8 is bigger than 5 you have to round up
Hundredth: 44.590
What is in the hundredth place?
The 8
What is to the right?
A 6
Since 6 is bigger than 5 you have to round up
Whole: 45
This us the same thing as rounding to the ones place.
What is in the ones place?
The second 4
What is to the right?
A 5
Since the 5 is big enough, it forces the 4 to round up.
Answer:
slope: || y-intercept: 3.5
Step-by-step explanation:
comparing with y = mx + b .....where m is slope and b is y-intercept.
slope is and y-intercept is 3.5
When you take a normal square root, that's also the same is raising to the 1/2 power. So you need the 5th root of 15, or 15^(1/5) = 1.71877...
BUT, multiplication comes first, order of operations
so 2.24 * 2 = 4.48
Add 15^(1/5) to 4.48 and keep as many decimals as you need
The slopes of the two lines are negative reciprocals.