Answer:

Step-by-step explanation:
see the attached figure to better understand the problem
step 1
Find the measure of angle KOM
In the triangle KOM
we have


Applying the law of cosines







step 2
Find the measure of the arc KM
we know that
----> by central angle
we have

so

step 3
Find the measure of angle KLM
we know that
The inscribed angle is half that of the arc comprising
![m\angle KLM=\frac{1}{2}[arc\ KM]](https://tex.z-dn.net/?f=m%5Cangle%20KLM%3D%5Cfrac%7B1%7D%7B2%7D%5Barc%5C%20KM%5D)
we have

substitute
![m\angle KLM=\frac{1}{2}[106.26^o]](https://tex.z-dn.net/?f=m%5Cangle%20KLM%3D%5Cfrac%7B1%7D%7B2%7D%5B106.26%5Eo%5D)

You add the exponents together when multiplying
gallon = pint *0.125
gallon = pint / 8
0.125+0.125+0.125+0.125+0.125+0.125+0.125+0.125+0.125+0.125+0.125+
0.125+0.125+0.125+0.125+0.125 = 2
16 would be the answer I believe, maybe I'm wrong, double check.
139,000,000 over 1, any number is a fraction just put it over 1
Answer:
I dont understand btw thanx for the points
Step-by-step explanation: