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djyliett [7]
3 years ago
13

£54,000 split ratio 1:3:8

Mathematics
1 answer:
Scrat [10]3 years ago
4 0
There are 12 parts to the ratio (1 + 3 + 8 = 12).
Divide 54,000 by 12.
54,000/12 = 4,500
Now multiply for each part:
1 = 4,500
3 = 13,500
8 = 36,000

You can check by adding them up (4,500 + 13,500 + 36,000 = 54,000).

So the ratio is 4,500:13,000:36,000

Hope this helps =)
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I need help this is hard please help me
Mademuasel [1]

Answer:

P(t)=25000+1.12t

Step-by-step explanation:

Now can you help me?

A basketball is thrown upwards. The height f(t), in feet, of the basketball at time t, in seconds, is given by the following function:

f(t) = −16t2 + 16t + 32

Which of the following is a reasonable domain of the graph of the function when the basketball falls from its maximum height to the ground?

3 0
3 years ago
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Which measurement is the largest 6 kilometers 60 meters 600 centimeters 6000 millimeters
Tju [1.3M]

6 kilometers is the greatest,but arranging from greatest to least: 6km, 60m, 600 cm or 6000mm


60 meters = 60 meters * 1km/1000 meters = 0.06 km600 centimeters = 600 cm * 1m/100cm * 1km/1000m = 0.006 km6000 millimeters = 6000mm * 1m/1000mm * 1km/1000m = 0.006km


<span>thus arranging from greatest to least:6km, 60m, 600 cm or 6000mm</span>

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I have to find out how many quarters and dimes equal $2.05 with 13 total coins
KatRina [158]

Answer:

Step-by-step explanation:

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3 years ago
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What is the solution of
Artemon [7]

Yo sup??

we can simply try option verification for this problem.

when x=0 we get,

1 and 1≠5 therefore x=0 is not a solution.

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when x=16 we get

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3 0
3 years ago
Preliminary data analyses indicate that it is reasonable to use a t-test to carry out the specified hypothesis test. Perform the
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<h2>Answer with explanation:</h2>

By considering the given information, we have

Null hypothesis : H_0: \mu=35.0

Alternative hypothesis : H_1: \mu\neq35.0

Since the alternative hypothesis is two-tailed , so the test is a two-tailed test.

Given : Sample size : n= 20, since sample size is less than 30 so the test applied is a t-test.

\overline{x}=41.0    ;    \sigma= 3.7

Test statistic : t=\dfrac{\overline{x}-\mu}{\dfrac{\sigma}{\sqrt{n}}}

i.e. t=\dfrac{41.0-35.0}{\dfrac{3.7}{\sqrt{20}}}=7.252112359\approx7.25

Degree of freedom : n-1 = 20-1=19

Significance level = 0.01

For two tailed,  Significance level =\dfrac{0.01}{2}=0.005

By using the t-distribution table, the critical value of t =t_{19, 0.005}=2.861

Since , the observed t-value (7.25) is greater than the critical value (2.861) .

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We conclude that there is some significance difference between the mean score for sober women and 35.0.

3 0
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