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zalisa [80]
3 years ago
7

Gustion1

Mathematics
1 answer:
yuradex [85]3 years ago
6 0

I will get a friend to help with this okay


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HELPPPPPPP PLZZZZ I DONT GET IT
expeople1 [14]

Answer:

See below

Step-by-step explanation:

1) \:  \frac{1}{2}  \times 5 \times 6 = 15 \:  {cm}^{2}  \\  \\ 2) \:  \frac{1}{2}  \times 10 \times 6 = 30 \:  {cm}^{2}   \\  \\ 3) \: 5 \times 3 = 15 \:  {cm}^{2}  \\  \\ 4) \: 10 \times 6= 60\:  {cm}^{2}

7 0
2 years ago
Translate each of these statements into logical expressions by using quatifiers and predicates with one or two variables. (a) A
nikdorinn [45]

Answer:

a) A = \{\exists x \in M, \exist y \in U\,|\,xGy \}, b) B = \{\exists x \in M,\,\exists y \in H\,|\,xMy \}, c) C = \{\forall x \in M\,|\,xI \}, d) D = \{\exists x \in M,\,\forall y \in U\,|\,xJy \} , e) E = \{\exists x \in M, \forall y \in V, V \subseteq U\,|\,xJy \}

Step-by-step explanation:

a) x - A student, M - Set of students of discrete math class, G - has lived in, y - Florida, U - Set of states of the United States of America.

A = \{\exists x \in M, \exist y \in U\,|\,xGy \}

b) x - A student, M - Set of students of discrete math class, y - A perfect grade, H - Midterm I.

B = \{\exists x \in M,\,\exists y \in H\,|\,xMy \}

c) x - A student, M - Set of students of discrete math class, I - loves discrete math.

C = \{\forall x \in M\,|\,xI \}

d) x - A student, M - Set of students of discrete math class, J - has been in, y - a state, U - Set of states of the United States of America.

D = \{\exists x \in M,\,\forall y \in U\,|\,xJy \}

e) x - A student, M - Set of students of discrete math class, J - has been in, y - a city, V - At least one state of the United States of America, U - Set of states of the United States of America.

E = \{\exists x \in M, \forall y \in V, V \subseteq U\,|\,xJy \}

5 0
3 years ago
What is the lcm of 8, 10 and 20
mestny [16]

Answer:

40

Step-by-step explanation:

Multiples of 8:

8, 16, 24, 32, 40, 48, 56

Multiples of 10:

10, 20, 30, 40, 50, 60

Multiples of 20:

20, 40, 60, 80

8 0
2 years ago
Please help. solve for x
malfutka [58]

Step-by-step explanation:

Given,

Base of the triangle

2 \sqrt{6}

Hypotenuse of the triangle = 5

Height of the triangle = x

Therefore, According to Pythagoras Theorem,

{base}^{2}  +  {height}^{2}  =  {hypotenuse}^{2}

=  >  {(2 \sqrt{6)} }^{2}  +  {x}^{2}  =  {5}^{2}

=  > 24 +  {x}^{2}  = 25

=  >  {x}^{2}  = 25 - 24

=  >  {x}^{2}  = 1

=  > x =  \sqrt{1}

=  > x = 1

Hence, the required value of <u>x is 1.</u>

7 0
2 years ago
12/15 in simplest form
alex41 [277]
\frac{12}{15} in simplest form:

First, find the greatest common factor (GCF) of 12, 15. 
Factors of 12: 1, 2, 3, 4, 6, 12
Factors of 15: 1, 3, 5, 15
The GCF is 3. 
Second, divide the numerator (12) by the GCF. / Your problem should look like: 12 ÷ 3 = 4
Third, divide the denominator (15) by the GCF. / Your problem should look like: 15 ÷ 3 = 5
Fourth, rewrite the fraction in the simplified form. / Your problem should look like: \frac{4}{5}

Answer: \frac{4}{5}

3 0
3 years ago
Read 2 more answers
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