Gustion1

expeople1 [14]

Answer:

See below

Step-by-step explanation:

$1) \: \frac{1}{2} \times 5 \times 6 = 15 \: {cm}^{2} \\ \\ 2) \: \frac{1}{2} \times 10 \times 6 = 30 \: {cm}^{2} \\ \\ 3) \: 5 \times 3 = 15 \: {cm}^{2} \\ \\ 4) \: 10 \times 6= 60\: {cm}^{2}$

7 0

2 years ago

Translate each of these statements into logical expressions by using quatifiers and predicates with one or two variables. (a) A

nikdorinn [45]

Answer:

a) $A = \{\exists x \in M, \exist y \in U\,|\,xGy \}$ , b) $B = \{\exists x \in M,\,\exists y \in H\,|\,xMy \}$ , c) $C = \{\forall x \in M\,|\,xI \}$ , d) $D = \{\exists x \in M,\,\forall y \in U\,|\,xJy \}$ , e) $E = \{\exists x \in M, \forall y \in V, V \subseteq U\,|\,xJy \}$

Step-by-step explanation:

a) x - A student, M - Set of students of discrete math class, G - has lived in, y - Florida, U - Set of states of the United States of America.

$A = \{\exists x \in M, \exist y \in U\,|\,xGy \}$

b) x - A student, M - Set of students of discrete math class, y - A perfect grade, H - Midterm I.

$B = \{\exists x \in M,\,\exists y \in H\,|\,xMy \}$

c) x - A student, M - Set of students of discrete math class, I - loves discrete math.

$C = \{\forall x \in M\,|\,xI \}$

d) x - A student, M - Set of students of discrete math class, J - has been in, y - a state, U - Set of states of the United States of America.

$D = \{\exists x \in M,\,\forall y \in U\,|\,xJy \}$

e) x - A student, M - Set of students of discrete math class, J - has been in, y - a city, V - At least one state of the United States of America, U - Set of states of the United States of America.

$E = \{\exists x \in M, \forall y \in V, V \subseteq U\,|\,xJy \}$

5 0

3 years ago

What is the lcm of 8, 10 and 20

mestny [16]

Answer:

40

Step-by-step explanation:

Multiples of 8:

8, 16, 24, 32, 40, 48, 56

Multiples of 10:

10, 20, 30, 40, 50, 60

Multiples of 20:

20, 40, 60, 80

8 0

2 years ago

Please help. solve for x

malfutka [58]

Step-by-step explanation:

Given,

Base of the triangle

$2 \sqrt{6}$

Hypotenuse of the triangle = 5

Height of the triangle = x

Therefore, According to Pythagoras Theorem,

${base}^{2} + {height}^{2} = {hypotenuse}^{2}$

$= > {(2 \sqrt{6)} }^{2} + {x}^{2} = {5}^{2}$

$= > 24 + {x}^{2} = 25$

$= > {x}^{2} = 25 - 24$

$= > {x}^{2} = 1$

$= > x = \sqrt{1}$

$= > x = 1$

Hence, the required value of <u>x is 1.</u>

7 0

2 years ago

12/15 in simplest form

alex41 [277]

$\frac{12}{15}$ in simplest form:

First, find the greatest common factor (GCF) of 12, 15.
Factors of 12: 1, 2, 3, 4, 6, 12
Factors of 15: 1, 3, 5, 15
The GCF is 3.
Second, divide the numerator (12) by the GCF. / Your problem should look like: 12 ÷ 3 = 4
Third, divide the denominator (15) by the GCF. / Your problem should look like: 15 ÷ 3 = 5
Fourth, rewrite the fraction in the simplified form. / Your problem should look like: $\frac{4}{5}$

Answer: $\frac{4}{5}$

3 0

3 years ago

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