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3 years ago

Find the percent of change. round to the nearest percent. original 132 new: 150

Mathematics

2 answers:

Ulleksa [173]3 years ago

5 0

Answer:

13.64%

Step-by-step explanation:

The increase, from 132 to 150, is 18.

Comparing 18 to the original 132, we get 18/132 = 0.1364

Rewriting this as a percentage change, we get 0.1364, or 13.64%. The percentage increase from 132 to 150 is 13.64%.

lbvjy [14]3 years ago

3 0

The percentage change is 18%

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PilotLPTM [1.2K]

Answer:

B)g(x) = 5^x - 10

Step-by-step explanation:

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The same thing happens if you compare other given points.

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3 years ago

Point L is on line segment \overline{KM}

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Answer:

KM = 4

Step-by-step explanation:

The point of the segment addition postulate is that the combined length of segments laid end-to-end is the sum of their individual lengths.*

KL +LM = KM

(5x +1) +(3x +3) = 5x +4

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3x = 0 . . . . . . . . . . subtract 5x+4

x = 0 . . . . . . . . . . . divide by 3

Then the length of KM is ...

KM = 5x +4 = 5·0 +4 = 0 +4

KM = 4

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3 years ago

A closed cylindrical vessel contains a fluid at a 5MPa pressure. The cylinder, which has an outside diameter of 2500mm and a wal

Julli [10]

Answer:

1) Increase in the diameter equals 3.5 mm

2) Increase in the length equals $0.0003724L_{i}$ where $L_{i}$ is the initial length of the vessel.

Step-by-step explanation:

The diametric strain in the vessel is given by

$\epsilon_{D} =\epsilon_{diam}-\nu \epsilon _{axial}$

We have

$\epsilon _{diam}=\frac{\sigma _{hoop}}{E}\\\\\sigma _{hoop}=\frac{\Delta P\times D}{2t}\\\\\therefore \epsilon _{diam}=\frac{\Delta P\times D}{2t\times E}$

Applying values we get

$\therefore \epsilon _{diam}=\frac{5\times 10^{6}\times 2.5}{2\times 20\times 10^{-3}\times 193\times 10^{9}}\\\\\therefore \epsilon _{diam}=\frac{5}{3088}$

Similarly axial strain is given by

$\epsilon _{diam}=\frac{\sigma _{axial}}{E}$

$\sigma _{axial}=\frac{\Delta P\times D}{4t}\\\\\therefore \epsilon _{axial}=\frac{\Delta P\times D}{4t\times E}$

Applying values we get

$\therefore \epsilon _{axial}=\frac{5\times 10^{6}\times 2.5}{4\times 20\times 10^{-3}\times 193\times 10^{9}}\\\\\therefore \epsilon _{diam}=\frac{2.5}{3088}$