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12345 [234]
3 years ago
8

Does anyone know the answer to this ?

Mathematics
2 answers:
Minchanka [31]3 years ago
4 0

Answer:

the answer is 2.5 mph

Step-by-step explanation:

speed= distance/time

speed=15/6

15 divided by 6 = 2.5

Akimi4 [234]3 years ago
3 0

Answer:

2.5mph

Step-by-step explanation:

S = Distance divided by Time (S = D/T)

Therefore.

S = 15/6

=2.5 mph

Colin walked an average speed of 2.5mph

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a¹⁰

Step-by-step explanation:

(x^{m} )^{n} =x^{mn}  

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A medical researcher wants to investigate the amount of time it takes for patients' headache pain to be relieved after taking a
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<span>A medical researcher wants to investigate the amount of time it takes for patients' headache pain to be relieved after taking a new prescription painkiller. She plans to use statistical methods to estimate the mean of the population of relief times. She believes that the population is normally distributed with a standard deviation of 18 minutes. How large a sample should she take to estimate the mean time to within 4 minutes with 97% confidence?
-----
n = [z*s/E]^2
---

n = [2.17*18/4]^2 = 96 when rounded up

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On the number line, a bug A is moving in the positive direction from the point 0, and a bug Bis moving in the negative direction
AleksAgata [21]

Answer:

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Step-by-step explanation:

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3 years ago
a normal distribution with a mean of 25 minutes with a population standard deviation of 5 minutes. The store manager sampled 100
sergiy2304 [10]

Answer:

z=\frac{24.25-25}{\frac{5}{\sqrt{100}}}=-1.5      

The p value for this case would be given with this probability:

p_v =P(z  

For this case since the p value is higher than the significance level of 0.01 we have enough evidence to fail to reject the null hypothesis and we don't have enough evidence to conclude that the true mean is significantly less than 25 min.

Step-by-step explanation:

Information given

\bar X=242.5 represent the sample mean      

\sigma=5 represent the population deviation

n=100 sample size      

\mu_o =25 represent the value to check

\alpha=0.01 represent the significance level

z would represent the statistic  

p_v represent the p value

Hypotheis to test

We want to verify if the true mean is less than 25 min, the system of hypothesis would be:      

Null hypothesis:\mu \geq 25      

Alternative hypothesis:\mu < 25      

The statistic would be given by:

z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}} (1)      

And replacing the info given we got:

z=\frac{24.25-25}{\frac{5}{\sqrt{100}}}=-1.5      

The p value for this case would be given with this probability:

p_v =P(z  

For this case since the p value is higher than the significance level of 0.01 we have enough evidence to fail to reject the null hypothesis and we don't have enough evidence to conclude that the true mean is significantly less than 25 min.

4 0
4 years ago
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