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Bingel [31]
3 years ago
11

The school that Trevon goes to selling tickets to the annual dance competition. On the first day of tickets sales the school sol

d 12 senior citizen tickets and 5 child tickets for a total of 85$. The school took in $75 on the second day by selling 6 senior citizen tickets and 9 child tickets. Find the price of a senior citizen ticket and the price of a child ticket.
Mathematics
1 answer:
KiRa [710]3 years ago
5 0

Answer:

  both kinds of tickets are $5 each

Step-by-step explanation:

Let s and c represent the dollar costs of a senior ticket and child ticket, respectively. The problem statement describes two relationships:

  12s + 5c = 85 . . . . . revenue from the first day of sales

  6s + 9c = 75 . . . . . . revenue from the second day of sales

Double the second equation and subtract the first to eliminate the s variable.

  2(6s +9c) -(12s +5c) = 2(75) -(85)

  13c = 65 . . . . . simplify

  65/13 = c = 5 . . . . . divide by the coefficient of c

Substitute this value into either equation. Let's use the second one.

  6s + 9·5 = 75

  6s = 30 . . . . . . . subtract 45

  30/6 = s = 5 . . . divide by the coefficient of s

The price of a senior ticket is $5; the price of a child ticket is $5.

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There are 1159 trees per acre because 98515/85 = 1159
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Find area and perimeter​
alisha [4.7K]

Answer:

Perimeter

P = P1+P2

P1 = 4a           P2=2(a+b)

P1=4*5           P2=2(3+5)

P1=20            P2=2*8

                     P2=16

P = 20+16

P=36

Area

A=A1+A2

A1=a^{2}                 A2=a*b

A1=5^{2}                 A2=3*5

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5 0
2 years ago
If the product of two positive fractions a and b is 15/56, find three pairs of possible values for a and b
Andrews [41]

Answer:

First possible pairs = (3/7)*(5/8) = 15/56

second possible pairs = (3/4)*(5/14) = 15/56

third possible pairs = (1/2)*(15/28) = 15/56

Step-by-step explanation:

According to the question,

a x b = 15/56

three possible pairs will be as follows:

Before proceeding to make possible pairs, we have to know the prime factorization of the numbers -

15 = 1, 3, 5, 15

56 = 1, 2, 4, 7, 8, 14, 28, 56

As we need three possible pairs, we have to check which pairs take us to 15/56. Again, since the fraction is positive, therefore, the fractions will be proper. Therefore, 3/2, or 5/4 will not be counted. Therefore,

First possible pairs = (3/7)*(5/8) = 15/56

second possible pairs = (3/4)*(5/14) = 15/56

third possible pairs = (1/2)*(15/28) = 15/56

fourth possible pairs = (3/8)*(5/7) = 15/56

So, we can get those four possible pairs. Among those, first 3 pairs are different. Therefore, those are possible pairs.

4 0
2 years ago
On a school trip, 4 adults are required to supervise a
lara31 [8.8K]

Answer:

5 adults

Step-by-step explanation:

So 4 adults are taken for 32 children. We can use 32 divided by 4 to see how many children it takes to assign an adult. the answer to this would be 8. if 8 more children are added ( which would make 32+8 which is 40) than another adult would be needed.

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2 years ago
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