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3 years ago

Can someone help pls

Mathematics

1 answer:

scZoUnD [109]3 years ago

3 0

Answer:

8) 10 m 9) 26 in 10) 51 m 11) 50 ft 12) 19.4 cm 13) 177.9 m 14) 40 15) 12 16) 14.7 17) 12.1

Step-by-step explanation:

You may solve the problems by using the Pythagorean Theorem which states that c^2 = a^2 + b^2, or in other words, the hypotenuse squared is equal to the sum of the legs squared.

Hope this helps! :-)

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Solve the following equation: |-3x+3|-9=12

photoshop1234 [79]

Answer:

$\large\boxed{\left \{ {{x\: = \: 8} \atop {x\: =\: -6}} \right. }\\$

Step-by-step explanation:

$\left| -3x+3 \right| -9=12$

At first, let's add - 9 to both the sides. So,

$\left| -3x+3 \right| -9=12\\|-3x+3|=21$

Now, using the definition of absolute value, we can change the equation to..

$-3x+3=21 \\-3x+3=-21$

By, subtracting 3 from both the sides,

$-3x=18 \\-3x=-24$

Now, divide both the sides by 6,

$x=-6 \\x=8$

We now have 2 values of x. They are...

$\large\boxed{\left \{ {{x\: = \: 8} \atop {x\: =\: -6}} \right. }\\$

____________

Hope it helps!

$\mathfrak{Lucazz}$

5 0

2 years ago

Out of a total of 300 crayons, 42 are blue. What percent of the crayons are blue?

Rzqust [24]

Answer:

14%

Step-by-step explanation:

42 is divisible of 3, the same with 300, if you put this equation into a fraction (42/300) and divide by 3, you should end up with 14/100 which is equal to 14%.

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4 years ago

Please solve the following picture!! due in 10 mins!

KiRa [710]

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3 years ago

If there is an 80% chance of rain and a 30% chance of wind and rain, what is the probability that it is windy, given that it is

algol13

We suppose the total chance is 100%. So the chance of wind and rain accounts for 30%. Then it is given rainy. So the total chance will change to 80% and the chance of wind and rain remains constant. Then you can get the answer should be 30%/80%=37.5%≈38%.

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4 years ago

The triangle shown is a right triangle. Solve for b.

ludmilkaskok [199]

The correct answer is C.

7 0

3 years ago

Can someone help pls​

Can someone help pls