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lora16 [44]
3 years ago
8

The sophomore class is planning to sell school mascot puppets to help cover the cost of a class trip. A local supplier will char

ge $76.25 for the design and $2.25 for each puppet ordered. The class plans to sell the puppets for $5. How many puppets must be sold to earn at least $2,000?
Mathematics
1 answer:
kifflom [539]3 years ago
8 0

Answer:

755 or more

Step-by-step explanation:

The profit is the difference between revenue and costs. We want the profit to be $2000 or more, and we have both fixed and variable costs.

Let x represent the number of puppets sold. Then the costs are ...

... 76.25 + 2.25x

The revenue is 5x.

The above-described relationship can then be written as

... 5x -(76.25 +2.25x) ≥ 2000

... 2.75x ≥ 2076.25 . . . . . add 76.25, collect terms

... x ≥ 2076.25/2.75 . . . . divide by the coefficient of x

... x ≥ 755

755 or more puppets must be sold to earn $2000 or more.

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Vector bought 15.6 pounds of paintballs. Ali together, the balls cost 35.99. About how much did the paintball cost per pound
Igoryamba

Answer:

<u>about $2.31 per pound</u>

Step-by-step explanation:

35.99/15.6 = 2.30705128205

2.31

Have a good day! :)

5 0
2 years ago
Complete the number sentence to show an example of the Distributive Property.
galben [10]
The answer would be 18

Hope that helps.
3 0
3 years ago
Brandon graphed one line in a system of equations. The system has only one solution, (0,3). Which equations could also be part o
AlladinOne [14]

Answer:

y = 3 and y = x + 3

Step-by-step explanation:

The equation y = 3 whose graph is a line parallel to x-axis can be a part of the system.

Consider the equation y = x + 3.

Substitute (0, 3).

3 = 0 + 3

So, (0, 3) lies on y = x + 3 and this can also be a part of the system.

6 0
2 years ago
Read 2 more answers
Aaron has a triathlon. Sunday he bikes 12 5/8 miles and swims 5 2/3 miles. Monday, he runs 6 3/8 miles. How many total miles Aar
Alla [95]
Let’s put these into one fraction each:

Biking:
= (12*5)/8 miles
= 60/8 miles
This can be reduced to,
= 15/2 miles

Swimming:
= (5*2)/3 miles
= 10/3 miles

Running:
= (6*3)/8 miles
= 18/8 miles
This can be reduced to,
= 9/4

Now we add all the distances up:
= (15/2) + (10/3) + (9/4)

Now we just can add the numerators and the denominators. We must find the lowest common factor (LCF) for our 3 denominators (2,3,4). Our LCF turns out to be 12. *Remember what we do to the denominator we must do to the numerator. So:
= (15/2) + (10/3) + (9/4)
= [(15*6)/12] + [(10*4)/12] + [(9*3)/12]
= (90/12) + (40/12) + (27/12)
= (157/12)
Therefore Aaron Ran 157/12 miles or 13.08 miles.

Hope this helps!
4 0
3 years ago
A multiple-choice examination has 20 questions, each with five possible answers, only one of which is correct. Suppose that one
kari74 [83]

Answer:

The probability that the student answers at least seventeen questions correctly is 8.03\times 10^{-10}.

Step-by-step explanation:

Let the random variable <em>X</em> represent the number of correctly answered questions.

It is provided all the questions have five options with only one correct option.

Then the probability of selecting the correct option is,

P(X)=p=\frac{1}{5}=0.20

There are <em>n</em> = 20 question in the exam.

It is also provided that a student taking the examination answers each of the questions with an independent random guess.

Then the random variable can be modeled by the Binomial distribution with parameters <em>n</em> = 20 and <em>p</em> = 0.20.

The probability mass function of <em>X</em> is:

P(X=x)={20\choose x}\ 0.20^{x}\ (1-0.20)^{20-x};\ x =0,1,2,3...

Compute the probability that the student answers at least seventeen questions correctly as follows:

P(X\geq 17)=P (X=17)+P (X=18)+P (X=19)+P (X=20)

=\sum\limits^{20}_{x=17}{{20\choose x}\ 0.20^{x}\ (1-0.20)^{20-x}}\\\\=0.00000000077+0.000000000032+0.00000000000084+0.000000000000042\\\\=0.000000000802882\\\\=8.03\times10^{-10}

Thus, the probability that the student answers at least seventeen questions correctly is 8.03\times 10^{-10}.

4 0
3 years ago
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