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Leto [7]
3 years ago
8

3 increased by the product of 4 and a number is equal to the same number decreased by 6. What is the number

Mathematics
1 answer:
nasty-shy [4]3 years ago
8 0

Answer:

1

Step-by-step explanation:


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Of the people who prefer mocha, the relative frequency of them preferring it cold is
WITCHER [35]

Answer

1) Relative frequency of prefering cold mocha amongst mocha drinkers = 0.32

2) Relative frequency of prefering a latte amongst hot coffee drinkers = 0.22

3) Type of coffee that has the highest percentage of people who prefer it cold = Regular

Explanation

1) Relative frequency of prefering cold mocha amongst mocha drinkers is given as

Relative frequency

= (Number of mocha drinkers who prefer it cold) ÷ (Total number of mocha drinkers)

Number of mocha drinkers who prefer it cold = 12

Total number of mocha drinkers = 12 + 25 = 37

Relative frequency = 12 ÷ 37 = 0.32

2) Relative frequency of prefering a latte amongst hot coffee drinkers is given as

Relative frequency

= (Number of latte drinkers who prefer it hot) ÷ (Total number of hot coffee drinkers)

Number of latte drinkers who prefer it hot = 19

Total number of hot coffee drinkers = 11 + 25 + 19 + 30 = 85

Relative frequency = (19/85) = 0.22

3) Percentage of people who prefer cold coffee for each coffee type

Regular

(17/28) = 60.7%

Mocha

(12/37) = 32.4%

Latte

(20/39) = 51.3%

Cappuccino

(27/57) = 47.4%

Regular coffee drinkers have the highest percentage of drinkers who prefer it cold.

Hope this Helps!!!

7 0
10 months ago
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Rina8888 [55]

Answer:

Step-by-step explanation:

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3 years ago
The graph below shows the number of napkins arranged on different numbers of tables in a room: A graph is shown. The values on t
DiKsa [7]
The point (1,14) shows that if there is one table in the room, then it will be set with 14 napkins. The other points show that if there are more tables in the room, the same ratio holds ... there will be 14 napkins on EACH table.
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Answer:

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Step-by-step explanation:


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Kryger [21]

Answer:

1)

Given the triangle RST with Coordinates  R(2,1), S(2, -2) and T(-1 , -2).

A dilation is a transformation which produces an image that is the same shape as original one, but is different size.  

Since, the scale factor \frac{5}{3} is greater than 1, the image is enlargement or a stretch.  

Now, draw the dilation image of the triangle RST with center (2,-2) and scale factor \frac{5}{3}

Since, the center of dilation at S(2,-2) is not at the origin, so the point S and its image S{}' are same.

Now, the distances from the center of the dilation at point S to the other points R and T.  

The dilation image will be\frac{5}{3} of each of these distances,

SR=3, so S{}'R{}'=5 ;


ST=3, so S{}'T{}'=5  

Now, draw the image of RST i.e R'S'T'

Since, RT=3\sqrt{2} [By using hypotenuse of right angle triangle] and R{}'T{}'=5\sqrt{2}.


2)

(a)

Disagree with the given statement.

Side Angle Side postulate (SAS) states that:

If two sides and the included angle of one triangle are congruent to two sides and the included angle of another triangle then these two triangles are congruent.

Given: B is the midpoint of \overline{AC} i.e \overline{AB}\cong \overline{BC}

In the triangle ABD and triangle CBD, we have

\overline{AB}\cong \overline{BC}   (SIDE)            [Given]

\overline{BD}\cong \overline{BD}   (SIDE)            [Reflexive post]

Since, there is no included angle in these triangles.

∴ \Delta ABD is not congruent to \Delta CBD .

Therefore, these triangles does not follow the SAS congruence postulates.

(b)

SSS(SIDE-SIDE-SIDE) states that if three sides of one triangle are congruent to three sides of another triangle, then the triangles are congruent.

Since it is also given that  \overline{AD}\cong \overline{CD}.

therefore, in the triangle ABD and triangle CBD, we have

\overline{AB}\cong \overline{BC}   (SIDE)            [Given]

\overline{AD}\cong \overline{CD}   (SIDE)           [Given]

\overline{BD}\cong \overline{BD}   (SIDE)            [Reflexive post]

therefore by, SSS postulates \Delta ABD\cong \Delta CBD.

3)

Given that:  \angle1=\angle 3 are vertical angles, as they are formed by intersecting lines.

Therefore

, by the definition of linear pairs

\angle 1 and \angle 2 and \angle 3  and \angle 2 are linear pair.

By linear pair theorem, \angle 1 and \angle 2   are supplementary, \angle 2 and \angle 3  are supplementary.

m\angle1+m\angle 2=180^{\circ}

m\angle2+m\angle 3=180^{\circ}

Equate the above expressions:

m\angle 1+m\angle 2=m\angle 2+m\angle 3

Subtract the angle 2 from both sides in the above expressions

∴m\angle 1=m\angle 3

By Congruent Supplement theorem: If two angles are supplements of the same angle, then the two angles are congruent.


therefore, \angle 1\cong \angle 3.















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2 years ago
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