Question

-16t^2+20t+65 Quadratic Formula

Answer 1

The value of T is

$\frac{-5+\sqrt{285} }{8}$ OR $\frac{-5-\sqrt{285} }{8}$

Step-by-step explanation:

Assumption: find the values of t

1. Equation is $-16t^{2}$+20t+65

2. Identify values of a, b and c

• a = -16
• b = 20
• c = 65

3. Write the quadratic formula

t = $\frac{-b±\sqrt{b^{2}-4ac } }{2a}$

4. Substitute the values of a, b and c in the formula

t = $\frac{-b±\sqrt{b^{2}-4ac } }{2a}$

t = $\frac{-20±\sqrt{20^{2}-4(-16)(65) } }{2(-16}$

5. Solve to find the possible values of t

t = $\frac{-20±\sqrt{20^{2}-4(-16)(65) } }{2(-16}$

• $\frac{-5+\sqrt{285} }{8}$ OR

• $\frac{-5-\sqrt{285} }{8}$

Keywords: Quadratic

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Answer 2

Step-by-step explanation:

16t^2+20t+65 Quadratic Formula