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KatRina [158]
3 years ago
12

Is 10=5x-6y written in standard form?

Mathematics
1 answer:
Lilit [14]3 years ago
7 0
No, the standard form for a straight line is in the form:

ax + by + c = 0

Since the 10 is on the LHS, you'd need to move it to the RHS to fit the straight line form and then moving everything to the LHS.

0 = 5x - 6y - 10
5x - 6y - 10 = 0 is the standard form.
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Can someone help please
pantera1 [17]

Answer:

45 degrees

Step-by-step explanation:

6 0
4 years ago
Solve for x <br> 8x+6=10 please help me ASAP
Alla [95]

Answer:

0.5

Step-by-step explanation:

8x+6=10

8x=10-6

8x=4

x=4/8=0.5

5 0
3 years ago
Read 2 more answers
Replace the ? with one of the following symbols (&lt;, &gt;, =, or ≠) for 4 + 3 + 7 ? 7 + 0 +7 A. &gt; B. ≠ C. = D. &lt;
ExtremeBDS [4]
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6 0
3 years ago
Graph a parabola whose intercepts are x=-3 and x=5 and whose minimum value is y =-4
blagie [28]

Answer:

y = 4(x^{2} + 8x + 15) = 4x^{2} + 32x + 60

Step-by-step explanation:

A parabola has the following format:

y = f(x) = ax^{2} + bx + c

If a is positive, it's minium value is:

y_{M} = -\frac{\bigtriangleup}{4a}

In which

\bigtriangleup = b^{2} - 4ac

Factoring:

ax^{2} + bx + c = a(x - x_{1})*(x - x_{2}), in which x_{1} and x_{2} are the intercepts.

In this question:

x_{1} = -5, x_{2} = -3

So

a(x - x_{1})*(x - x_{2}) = a*(x - (-5))*(x - (-3)) = a*(x+5)*(x+3) = a*(x^{2} + 8x + 15)

Suppose a = 1, we have:

x^{2} + 8x + 15

\bigtriangleup = 8^{2} - 4*1*15 = 4

The minimum value will be:

y_{M} = -\frac{4}{4} = -1

We want this minimum value to be -4, which is 4 times the current minimum value, so we need to multiply a by 4. Then

a = 4

And the parabola is:

y = 4(x^{2} + 8x + 15) = 4x^{2} + 32x + 60

4 0
3 years ago
Savannah bought 14 chicken wings for $30.80. How much would it cost for 23 wings?
raketka [301]
$50.80

Each wing cost $2.20 so if you multiply that by 23 you’ll get 50.80
8 0
2 years ago
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