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marin [14]
3 years ago
13

Does a dilation produce a congruent figure

Mathematics
2 answers:
ANEK [815]3 years ago
7 0

Answer:

A dilation is a transformation that produce an image that is the same shape as the original,but is a different size.A dilation that creates a larger image is called an enlargement.A dilation that creates a smaller image is called a reduction. ...... if the scale factor is 1,the figure and the image are congruent.

Step-by-step explanation:

Sauron [17]3 years ago
5 0
A dilation is a transformation that produces an image that is the same shape as the original, but is a different size. A dilation that creates a larger image is called an enlargement. ... If the scale factor is 1, the figure and the image are congruent. The word "dilate" is often heard in relation to the human eye.
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4 years ago
At a school concert,the orchestra plays 8 songs that are 4.25 min long and 3 songs that are twice as long as each of the others.
Kazeer [188]

Answer: 59.5 minutes.


Step-by-step explanation:

1. You have the following information given in the problem above:

- 8 songs are 4.25 minutes long.

- 3 songs are twice as long as each of the others.

2. Therefore, the total time of 8 songs is:

(8)(4.25min)=34min

3. And the total time of the 3 songs is:

(2)(3)(4.25min)=25.5min

4. Therefore, you have that the result is:

34min+25.5min=59.5min

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4 years ago
In the equation y=56x, number 56 represents?
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Answer:

The constant of proportionality

Step-by-step explanation:

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3 years ago
Gina has a spinner with five equal parts numbered one thru five. If Gina spins the spinner one time, what is the probability tha
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Answer:

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Step-by-step explanation:

3 0
3 years ago
An article reports on an experiment in which each of five groups consisting of six rats was put on a diet with a different carbo
loris [4]

Answer:

H0 is rejected, Hence the true average DNA content is affected by the type of carbohydrate in the diet between samples

Step-by-step explanation:

<u> A              B               C          D              E</u>

<u>2.58 2.63 2.13          2.41    2.49</u>

∑A=2.58 ∑B=2.63 ∑C=2.13  ∑D=2.41   ∑E=2.49

<u>A²                           B²                C²               D²             E²</u>

<u>6.6564               6.9169 4.5369             5.8081 6.2001</u>

∑A²=6.6564 ∑B²=6.9169 ∑C²=4.5369 ∑D²=5.8081 ∑E²=6.2001

Calculations

<u>Group A            B           C           D             E       Total</u>

<u>N      n1=1         n2=1 n3=1 n4=1 n5=1 n=5</u>

∑xi T1=2.58    T2=2.63 T3=2.13 T4=2.41 T5=2.49 ∑x=12.24

<u>∑x²i  6.6564      6.9169 4.5369 5.8081 6.2001 ∑x²=30.1184</u>

<u>Mean xi 2.58 2.63 2.13          2.41         2.49 Total2.448</u>

Σ Σ xij^2 = 185.4 given

Let k = the number of different samples = 5

n=n1+n2+n3+n4+n5=1+1+1+1+1=5

Overall ˉx=12.24/5  =2.448

∑x=T1+T2+T3+T4+T5=2.58+2.63+2.13+2.41+2.49=12.24----1

Correction Factor=(∑x)²/n=12.242/5=29.9635--------(2)

∑T²i/ni=(2.582/1+2.632/1+2.132/1+2.412/1+2.492/1)=30.1184------(3)

∑x²=∑x²1+∑x²2+∑x²3+∑x²4+∑x²5

=6.6564+6.9169+4.5369+5.8081+6.2001=30.1184-------(4)

ANOVA:

Step-1 : sum of squares between samples

SSB=(∑T2i/ni)-(∑x)2/n

=(3)-(2)

=30.1184-29.9635

=0.1549

Step-2 : Total sum of squares

SST=SSB-CF

= 185.4-2.488

=182.952

Step-3 : Sum of Squares Within Samples

SSW=∑x²-(∑T²i/ni)=SST- SSB=

        = 182.952-0.1549=182.7971

Step-4 : variance between samples

MSB=SSB/k-1

=0.1549/4

=0.0387

Step-5 : variance within samples

MSW=SSW/n-k

=182.7971/5-5

=36.55942

Step-6 : test statistic F for one way ANOVA test

F=MSB/MSW

=0.0387/36.55942 = 0 .001058

<u>ANOVA table</u>

Source               Sums                  Degrees        Mean

of Variation    of Squares       of freedom        Squares

                                SS                        DF                 MS              F

B/w samples         SSB = 0.1549        k-1 = 4 MSB = 0.0387 0.001

<u>Within samples  SSW = 0               n-k = 0 MSW = 36.55942  </u>

<u>Total                  SST = 0.1549       n-1 = 4   </u>

H0 : The true average DNA content is not affected by the type of carbohydrate in the diet between samples

Ha : The true average DNA content is affected by the type of carbohydrate in the diet between samples

F(4,0) at 0.05 level of significance =0.5

As calculated F=0.001 >0.5

So, H0 is rejected, Hence the true average DNA content is affected by the type of carbohydrate in the diet between samples

6 0
3 years ago
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