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3 years ago

What is a task that an internet database allows you to perform

Computers and Technology

2 answers:

Ira Lisetskai [31]3 years ago

8 0

The Internet Database allows you to view a ton of knowledge all from the comfort of your own in less then 16 seconds.

Andreas93 [3]3 years ago

3 0

Answer:

A task that an internet database allows you to perform is discussed below.

Explanation:

The Internet is utilized for various items, such as computerized mail, online chatting, data transfer and other certificates of the World Wide Web.
The common related assistance on the Internet is the World Wide Web which is also designated the "Web" or “www”.
The web carries websites, involved blogs and ocean of Information like Wikipedia.

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Program MATH_SCORES: Your math instructor gives three tests worth 50 points each. You can drop one of the test scores. The final

Simora [160]

Answer:

import java.util.Scanner;

public class num5 {

public static void main(String[] args) {

Scanner in = new Scanner(System.in);

//Prompt and receive the three Scores

int score1;

int score2;

int score3;

do {

System.out.println("Enter first Score Enter score between 1 -50");

score1 = in.nextInt();

} while(score1>50 || score1<0);

do {

System.out.println("Enter second Score.The second score must be between 1 -50");

score2 = in.nextInt();

} while(score2>50 || score2<0);

do {

System.out.println("Enter Third Score Third score must between 1 -50");

score3 = in.nextInt();

} while(score3>50 || score3<0);

//Find the minimum of the three to drop

int min, min2, max;

if(score1<score2 && score1<score3){

min = score1;

min2 = score2;

max = score3;

}

else if(score2 < score1 && score2<score3){

min = score2;

min2 = score1;

max = score3;

}

else{

min = score3;

min2 = score1;

max = score2;

}

System.out.println("your entered "+max+", "+min2+" and "+min+" the min is");

int total = max+min2;

System.out.println("Total of the two highest is "+total);

//Finding the grade based on the cut-off points given

if(total>=90){

System.out.println("Grade is A");

}

else if(total>=80){

System.out.println("Grade is B");

}

else if(total>=70){

System.out.println("Grade is C");

}

else if(total>=60){

System.out.println("Grade is D");

}

else{

System.out.println("Grade is F");

}

Explanation:

Implemented with Java
Use the scanner class to receive user input
Use a do.....while loop to validate user input for each of the variables. A valid score must be between 0 and 50 while(score>50 || score<0);
Use if and else to find the minimum of the three values and drop
Add the two highest numbers
use if/else if /else statements to print the corresponding grade

8 0

3 years ago

Which employees work directly with customers, helping them make deposits and withdrawals?

d1i1m1o1n [39]

I believe the answer is customer service

5 0

3 years ago

Read 2 more answers

Explain briefly the FIREWALLS

Vlada [557]

Answer:

Think of a firewall as your own personal security guard. The firewall will block unapproved websites from talking to your computer and will stop your computer from talking to unapproved/unnecessary websites. Hope this helps!

Explanation:

7 0

3 years ago

Pseudocode of creating a program to convert to IEEE 754 to a real number

Eduardwww [97]

Answer:

Step1: Check If the number is Positive or Negative.
Step2: If it is positive then save the sign of it as 0.
Step3: If it is negative then save the sign of it as 1.
Step4: Covert the negative number to Positive.
Step5: Convert the IEEE 754 to Binary.
Step6: convert the integer part into binary form
Step7: Convert fractional part into binary form
Step8: To convert Integer part, Devide the number by 2 and note down the reminder and Keep deviding unless dividend is less than 2
Step9: copy all the reminders together
Step10: Multiply decimal part by 2 unless fractional part is 0.
Step11: By noting down integral part, keep multiplying decimal part by new value of 2 untill perfect number is reached.
Step6: Find the Mantissa.
Step7: Concatinate the Sign, exponent and the mantissa.

Explanation:

For Example : 20.75

First step (converting 50 (in base 10) to binary):

No is Positive
By dividing 20 by 2, which gives 10 with no remainder 0.
Now Devide 10 by 2, which gives 5 with a remainder of 0.
Now Devide 5 by 2, which gives 2 the reminder as 1
Now Devide 2 by 2, which gives 1 with reminder as 0
Now devide 1 by 2, which gives 0 with reminder as 1
We read the result from bottom to top which is 10100

Second part is to convert 0.75 to binary:

We have to multiply 0.75 by 2, which gives 1.5. We keep only the integer part, which is 1.
Now, we do 1.5 - 1, which gives 0.5. Now, We multiply 0.5 by 2, which gives 1.
Now we do 1 - 1, which gives 0.
Reading from Top to bottom will give 110

Final Answer is : 10100.110

8 0

3 years ago

C++ code only

nordsb [41]

Using the computational language C++ it is possible to write a code is possible to create a function that stores items like this:

<h3>Writting the code in C++: </h3>

//Header files

#include <iostream>

#include <string>

#include <fstream>

using namespace std;

//Class inventoryItem

class inventoryItem

{

public:

//Variable declaration

string itemName;

string itemNumber;

double itemPrice;

int itemQuantity;

};

//implementation of menuItems() function.

void menuItems()

{

// Display the Menu

cout << "=============================\n";

cout << " 1) Add an item to memory\n"

<< " 2) Search memory for an item \n"

<< " 3) List what's in memory\n"

<< " 4) Total value on hand\n"

<< " 5) Save to a file\n"

<< " 6) Read from a file\n"

<< " 0) Exit Program" << endl;

}

//main method.

int main()

{

//variable declaration.

int mnuChoice, cn = 0, d;

string n;

double sum = 0, c;

int temp;

string a, b;

string inputBuffer;

inventoryItem items[100];

ifstream inventoryFile("inventory.txt");

if (inventoryFile)

{

//store the data from the file to memory.

while (!(inventoryFile.eof()))

{

inventoryFile >> items[cn].itemName;

inventoryFile >> items[cn].itemNumber;

inventoryFile >> inputBuffer;

items[cn].itemPrice = atof(inputBuffer.c_str());

inventoryFile >> inputBuffer;

items[cn].itemQuantity = atoi(inputBuffer.c_str());

cn++;

}

inventoryFile.close();

ifstream inventoryFile("inventory.txt");

ofstream fout;

fout.open("inventory.txt");

do

{

menuItems();

cout << cn << " items stored." << endl;

// Prompt and read choice form the user

cout << "Enter your choice: ";

cin >> mnuChoice;

switch (mnuChoice)

{

//Add a new inventory item to the data in memory.

case 1:

// Prompt and read name of the item from the user

cout << "Enter name of the item: ";

cin >> inputBuffer;

items[cn].itemName = inputBuffer;

// Prompt and read itemNumber from the user

cout << "Enter the itemNumber: ";

cin >> inputBuffer;

items[cn].itemNumber = inputBuffer;

// Prompt and read itemPrice from the user

cout << "Enter the itemPrice: ";

cin >> inputBuffer;

items[cn].itemPrice = atof(inputBuffer.c_str());

// Prompt and read itemQuantity from the user

cout << "Enter the itemQuantity: ";

cin >> inputBuffer;

items[cn].itemQuantity = atoi(inputBuffer.c_str());

cn++;

break;

//Search the inventory for an item by inventory number.

case 2:

temp = 0;

cout << "Enter inventory itemNumber: ";

cin >> n;

for (int i = 0; i < cn&&temp != 1; i++)

{

// If found, print the stored info

if (items[i].itemNumber.compare(n) == 0)

{

// Display the stored information

cout << "Item Name" << "\t" << "Item Number" << "\t" << " Item Price" << "\t" << " Item Quantity" << endl;

cout << items[i].itemName << "\t " << items[i].itemNumber << " \t" << items[i].itemPrice << "\t " << items[i].itemQuantity << endl;

temp = 1;

}

// otherwise print 'not found'.

if (temp == 0)

{

cout << "Not found!!!" << endl;

}

break;

//List the inventory on the screen

case 3:

cout << "The data in the memory is:" << endl;

cout << "Item Name" << "\t" << "Item Number" << "\t" << " Item Price" << "\t" << " Item Quantity" << endl;

for (int i = 0; i < cn; i++)

{

cout << items[i].itemName << "\t " << items[i].itemNumber << "\t " << items[i].itemPrice << " \t" << items[i].itemQuantity << endl;

}

break;

// Calculate the total value on hand.

case 4:

for (int i = 0; i < cn; i++)

{

// The sum is the accumulation of all the (quantities * prices).

sum += items[i].itemPrice*items[i].itemQuantity;

}

cout << "sum value on hand: " << sum << endl;

break;

// Save the inventory data in the given file

case 5:

for (int i = 0; i < cn; i++)

{

if (i == cn - 1)

{

fout << items[i].itemName << " \t" << items[i].itemNumber << " \t" << items[i].itemPrice << " \t" << items[i].itemQuantity;

}

else

{

fout << items[i].itemName << " \t" << items[i].itemNumber << " \t" << items[i].itemPrice << " \t" << items[i].itemQuantity << endl;

}

break;

// Read the data from the file

case 6:

while (!(inventoryFile.eof()))

{

inventoryFile >> a;

inventoryFile >> b;

inventoryFile >> inputBuffer;

c = atof(inputBuffer.c_str());

inventoryFile >> inputBuffer;

d = atoi(inputBuffer.c_str());

// Dsiplays the data in the file

cout << a << " " <

}

break;

}

// Check the menu choice is not equal to 0,

//if it is equal exit from the loop

} while (mnuChoice != 0);

// File closed

fout.close();

inventoryFile.close();

}

// If the inventory file does not exist

// and then display the error message.

else

{

cout << "File does not exist!" << endl;

}

return 0;

}

See more about C++ code at brainly.com/question/17544466

#SPJ1

5 0

2 years ago