18. What is the slope of a line perpendicular to y=1/3x - 2

Mathematics

1 answer:

Nadya [2.5K]3 years ago

5 0

Answer:

The slop of line perpendicular to line y = $\frac{1}{3}$ x - 2 is ( - 3)

Step-by-step explanation:

Given Line equation as ,

y = $\frac{1}{3}$ x - 2

The equation of line is y = mx + c

Slop of this line (m1) = $\frac{1}{3}$

Now second line with slop (m2) is perpendicular to line first , then

(m1) × (m2) = - 1

So, (m2) = $\frac{-1}{m1}$

Or , (m2) = $\frac{-1}{\frac{1}{3}}$

∴ (m2) = - 3

Hence the slop of line perpendicular to line y = $\frac{1}{3}$ x - 2 is ( - 3) Answer

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