What is the period of y=3cot(4x−3π)
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The equation in slope-intercept form for the line that passes through the point ( -1 , -2 ) and is perpendicular to the line − 4 x − 3 y = − 5 is
<em><u>Solution:</u></em>
<em><u>The slope intercept form is given as:</u></em>
y = mx + c ----- eqn 1
Where "m" is the slope of line and "c" is the y - intercept
Given that the line that passes through the point ( -1 , -2 ) and is perpendicular to the line − 4 x − 3 y = − 5
Given line is perpendicular to − 4 x − 3 y = − 5
− 4 x − 3 y = − 5
-3y = 4x - 5
3y = -4x + 5
On comparing the above equation with eqn 1, we get,
We know that product of slope of a line and slope of line perpendicular to it is -1
Given point is (-1, -2)
Now we have to find the equation of line passing through (-1, -2) with slope
Substitute (x, y) = (-1, -2) and m = 3/4 in eqn 1
Thus the required equation of line is found