What is the period of y=3cot(4x−3π)

1 answer:

4 0

Hello!

hint: we can rewrite your function as below:

3/tan(4x−3π) = 3(1+tan4xtan3π)/tan4x−tan3π =

=3/tan(4x) = 3cot(4x)

now, since the period P of cotangent function is pi, then the period of cot(4x), which is the period of our original function, is such that:

"4P=π"

Hope this Helps! Have A Wonderful Day! :)

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