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solniwko [45]
3 years ago
10

What is the period of y=3cot(4x−3π)

Mathematics
1 answer:
Stells [14]3 years ago
4 0
Hello!

hint: we can rewrite your function as below:

<span>3/<span>tan<span>(<span>4x−3π</span>) = </span></span></span>3(1+tan4xtan3π)/tan4x−tan3π = 

=<span>3/<span>tan<span>(<span>4x</span>) = </span></span></span>3cot<span>(<span>4x</span><span>)

</span></span>now, since the period P of cotangent function is pi, then the period of cot(4x), which is the period of our original function, is such that:

<span>"4P=π"


Hope this Helps! Have A Wonderful Day! :)</span>
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