What is the answer to y=2x+1
2 answers:
Answer: x= y-1/2
How to solve:
1. Subtract 1 from both sides.
2x=y-1
2. Divide both sides by 2
X=y-1/2
This equation looks like it is using the formula y=mx+b. You should attempt to graph it.
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Answer: B. 41
skfjfhdjkslskfjf
Answer:
k(-7) = = -89
Step-by-step explanation:
k(t) = 10t -19
Let t = -7
k(-7) = 10*-7 -19
= -70-19
= -89
Answer:
3x-4y-9
Step-by-step explanation:
Combine like terms
Let
![t=\sqrt y](https://tex.z-dn.net/?f=t%3D%5Csqrt%20y)
, so that
![t^2=y](https://tex.z-dn.net/?f=t%5E2%3Dy)
,
![t^4=y^2](https://tex.z-dn.net/?f=t%5E4%3Dy%5E2)
, and
![\mathrm dt=\dfrac{\mathrm dy}{2\sqrt y}](https://tex.z-dn.net/?f=%5Cmathrm%20dt%3D%5Cdfrac%7B%5Cmathrm%20dy%7D%7B2%5Csqrt%20y%7D)
. Then
![\displaystyle\int\frac t{t^4+2}\,\mathrm dt=\int\frac{\sqrt y}{2\sqrt y(y^2+2)}\,\mathrm dy=\frac12\int\frac{\mathrm dy}{y^2+2}](https://tex.z-dn.net/?f=%5Cdisplaystyle%5Cint%5Cfrac%20t%7Bt%5E4%2B2%7D%5C%2C%5Cmathrm%20dt%3D%5Cint%5Cfrac%7B%5Csqrt%20y%7D%7B2%5Csqrt%20y%28y%5E2%2B2%29%7D%5C%2C%5Cmathrm%20dy%3D%5Cfrac12%5Cint%5Cfrac%7B%5Cmathrm%20dy%7D%7By%5E2%2B2%7D)
Now let
![y=\sqrt2\tan z](https://tex.z-dn.net/?f=y%3D%5Csqrt2%5Ctan%20z)
, so that
![\mathrm dy=\sqrt2\sec^2z\,\mathrm dz](https://tex.z-dn.net/?f=%5Cmathrm%20dy%3D%5Csqrt2%5Csec%5E2z%5C%2C%5Cmathrm%20dz)
. Then
![\displaystyle\frac12\int\frac{\mathrm dy}{y^2+2}=\frac12\int\frac{\sqrt2\sec^2z}{(\sqrt2\tan z)+2}\,\mathrm dz=\frac{\sqrt2}4\int\frac{\sec^2z}{\tan^2z+1}\,\mathrm dz=\frac1{2\sqrt2}\int\mathrm dz=\dfrac1{2\sqrt2}z+C](https://tex.z-dn.net/?f=%5Cdisplaystyle%5Cfrac12%5Cint%5Cfrac%7B%5Cmathrm%20dy%7D%7By%5E2%2B2%7D%3D%5Cfrac12%5Cint%5Cfrac%7B%5Csqrt2%5Csec%5E2z%7D%7B%28%5Csqrt2%5Ctan%20z%29%2B2%7D%5C%2C%5Cmathrm%20dz%3D%5Cfrac%7B%5Csqrt2%7D4%5Cint%5Cfrac%7B%5Csec%5E2z%7D%7B%5Ctan%5E2z%2B1%7D%5C%2C%5Cmathrm%20dz%3D%5Cfrac1%7B2%5Csqrt2%7D%5Cint%5Cmathrm%20dz%3D%5Cdfrac1%7B2%5Csqrt2%7Dz%2BC)
Transform back to
![y](https://tex.z-dn.net/?f=y)
to get
![\dfrac1{2\sqrt2}\arctan\left(\dfrac y{\sqrt2}\right)+C](https://tex.z-dn.net/?f=%5Cdfrac1%7B2%5Csqrt2%7D%5Carctan%5Cleft%28%5Cdfrac%20y%7B%5Csqrt2%7D%5Cright%29%2BC)
and again to get back a result in terms of
![t](https://tex.z-dn.net/?f=t)
.
Answer:
Step-by-step explanation:
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