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3 years ago

How do I solve this problem

Mathematics

1 answer:

DaniilM [7]3 years ago

6 0

Answer:

trrtrtrtrtrtrtrtrt

Step-by-step explanation:

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43.586 to the nearest tenth, hundredth, and one.

Alex777 [14]

<span>43.586 to the nearest tenth is 43.6. That is because 43.586 is greater than 43.55 and we have to increase the tenth value for 1. And 43.586 to the nearest hunderth is 43.59. That is because 43.586 is greater than 43.585. Finally, 43.586 to the nearest whole number is 44 ( 43.586 is greater than 43.5 ). Hope this helps. Let me know if you need additional help!</span>

5 0

4 years ago

Which method correctly solves the equation using the multiplication property of equality and the reciprocal of One-third? One-th

Airida [17]

Answer:

Step-by-step explanation:

Given the equation $\frac{1}{3}(x+9) = -12$

Step 1;

Expand the bracket at the right hand side of the equation to have:

$\frac{1}{3}x +\frac{1}{3}(9) = -12\\\frac{1}{3}x+3=-12\\subtracting\ 3\ from\ both\ sides\\\frac{1}{3}x+3-3=-12-3\\\frac{1}{3}x=-15\\$

Taking the reciprocal of both sides:

$\frac{3}{x} = \frac{-1}{15} \\ cross\ multiplying\\-x =45\\x=-45$

4 0

3 years ago

Read 2 more answers

Two sets of equatic expressions are shown below in various forms: Line 1: x2 + 3x + 2 (x + 1)(x + 2) (x + 1.5)2 − 0.25 Line 2: x

kherson [118]

Answer: The correct line is

$\textup{Line 1 :}x^2+3x+2=(x+1)(x+2)=(x+1.5)^2-0.25.$

Step-by-step explanation: We are given the following two sets of quadratic expressions in various forms:

$\textup{Line 1: }x^2+3x+2=(x+1)(x+2)=(x+1.5)^2-0.25,\\\\\textup{Line 2 :}x^2+5x+6=(x+2)(x+3)=(x+2.5)^2+6.25.$

We are to select one of the lines from above that represent three equivalent expressions.

We can see that there are three different forms of a quadratic expression in each of the lines:

First one is the simplified form, second is the factorised form and third one is the vertex form.

So, to check which line is correct, we need to calculate the factorised form and the vertex form from the simplified form.

We have

$\textup{Line 1: }\\\\x^2+3x+2\\\\=x^2+2x+x+2\\\\=x(x+2)+1(x+2)\\\\=(x+1)(x+2),$

and

$x^2+3x+2\\\\=x^2+2\times x\times 1.5+(1.5)^2-(1.5)^2+2\\\\=(x+1.5)^2-2.25+2\\\\=(x+1.5)^2-0.25.$

So,

$\textup{Line 1 :}x^2+3x+2=(x+1)(x+2)=(x+1.5)^2-0.25.$

Thus, Line 1 contains three equivalent expressions.

Now,

$\textup{Line 2: }\\\\x^2+5x+6\\\\=x^2+3x+2x+6\\\\=x(x+3)+2(x+3)\\\\=(x+2)(x+3),$

and

$x^2+5x+6\\\\=x^2+2\times x\times 2.5+(2.5)^2-(2.5)^2+6\\\\=(x+2.5)^2-6.25+6\\\\=(x+2.5)^2-0.25\neq (x+2.5)^2+6.25.$

So,

$\textup{Line 2 :}x^2+3x+2=(x+1)(x+2)=(x+1.5)^2+6.25.$

Thus, Line 2 does not contain three equivalent expressions.

Hence, Line 1 is correct.

7 0

4 years ago

What was haley’s function in standard form

Stels [109]

Answer: 7,-10,-2

Step-by-step explanation:

3 0

3 years ago

2y-x=6 and y=2x+7 graphed equals how many solutions

zhannawk [14.2K]

Answer:

One solution

<em>BRAINLIEST, PLEASE!</em>

Step-by-step explanation:

2y - x = 6

2y = x + 6

y = x/2 + 3

y = 2x + 7

After graphing, they have one solution at (-2.667, 1.667).

8 0

3 years ago