Answer:
We have the next relation:
A = (b*d)/c
because we have direct variation with b and d, but inversely variation with c.
Now, if we have 3d instead of d, we have:
A' = (b*(3d))/c
now, we want A' = A. If b,c, and d are the same in both equations, we have that:
3bd/c = b*d/c
this will only be true if b or/and d are equal to 0.
If d remains unchanged, and we can play with the other two variables we have:
3b'd/c' = bd/c
3b'/c' = b/c
from this we can took that: if c' = c, then b' = b/3, and if b = b', then c' = 3c.
Of course, there are other infinitely large possible combinations that are also a solution for this problem where neither b' = b or c' = c
I have drawn three obtuse angles showing three different positions.
then taken a point p inside it.
Now to draw perpendicular from a point to a given line
we draw a line parallel fom that point to that given line.
After that from that point we draw perpendicular to that line.
Now the question arises which side is closer to point p ,
The answer is if length of perpendicular from p to the line is longer that side is farther from the point p , and if the length of perpendicular is shorter then that that line is nearer to point P.
It would b 5 !!!!!!!!!!!!!!!!!!!!
<h3>⚠ANSWER⚠</h3>
<em><u>↪</u></em><em><u>Given 15 cot A = 8. Find sin A and sec A </u></em>
Hope this helps...☆
Answer:
The length is 91 meters
Step-by-step explanation:
The perimeter formula is 2W · 2L = 314
We know the width is 66 m, so we can then say:
132 · 2L = 314
-132 -132
2L = 182
L = 91
Hope this helped!
