Please help fast!! this si my last question!

Convert F2 from hexadecimal to binary.

Yakvenalex [24]

Question:

"Convert F2 from hexadecimal to binary."

Answer:

11110010

Step-by-step explanation:

Hex F2 to decimal explained:

The value of HEX F2 in decimal is 242.

The value of HEX F2 in binary is 11110010.

2 2 X 160 = 2

F 15 X 161 = 240

HEX F2 = 242

The binary value is: 11110010

A hexadecimal number has base 16 (0,1,2,3,4,5,6,7,8,9 A,B,C,D,E,F).

basic hex to a decimal conversion table

Hex 0 1 2 3 4 5 6 7 8 9 A B C D E F

Decimal 0 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15

HOPE THIS HELPS!

PLEASE MARK BRAINLIEST IF THIS HELPED YOU LEARN! :)

3 0

2 years ago

Multiple the binomials (x+3)^2

maxonik [38]

Answer:

$=x^2+6x+9$

Step-by-step explanation:

$\left(x+3\right)^2\\\mathrm{Apply\:Perfect\:Square\:Formula}:\quad \left(a+b\right)^2=a^2+2ab+b^2\\a=x,\:\:b=3\\=x^2+2x\cdot \:3+3^2\\\mathrm{Simplify}\:x^2+2x\cdot \:3+3^2:\quad x^2+6x+9\\x^2+2x\cdot \:3+3^2\\\mathrm{Multiply\:the\:num\\bers:}\:2\cdot \:3=6\\=x^2+6x+3^2\\3^2=9\\=x^2+6x+9$

8 0

3 years ago

Write the equation of the line that passes through the points (-6, -9) and

e-lub [12.9K]

Answer:

y - 7 = 16/13(x - 7)

General Formulas and Concepts:

Alg I

Point-Slope Form: y - y₁ = m(x - x₁)

x₁ - x coordinate

y₁ - y coordinate

m - slope

Slope Formula: $m=\frac{y_2-y_1}{x_2-x_1}$

Step-by-step explanation:

Step 1: Define

Point (-6, -9)

Point (7, 7)

Step 2: Find slope m

Substitute: $m=\frac{7+9}{7+6}$
Add: $m=\frac{16}{13}$

Step 3: Write equation

y - 7 = 16/13(x - 7)

3 0

3 years ago

Conver the equation y=2 to polar form. Then solve the resulting equation for r. Thanks :)

maksim [4K]

This is something to memorize

y = r*sin(theta)

so if y = 2, then

2 = r*sin(theta)

Divide both sides by sin(theta) to get

r = 2/sin(theta)
r = 2csc(theta)

8 0

3 years ago

A survey of 76 commercial airline flights of under 2 hours resulted in a sample average late time for a flight of 2.55 minutes.

nika2105 [10]

Answer:

The best point of estimate for the true mean is:

$\hat \mu = \bar X = 2.55$

$2.55-1.96\frac{12}{\sqrt{76}}=-0.148$

$2.55+1.96\frac{12}{\sqrt{76}}=5.248$

Since the time can't be negative a good approximation for the confidence interval would be (0,5.248) minutes. The interval are tellling to us that at 95% of confidence the average late time is lower than 5.248 minutes.

Step-by-step explanation:

Information given

$\bar X=2.55$ represent the sample mean for the late time for a flight

$\mu$ population mean

$\sigma=12$ represent the population deviation

n=76 represent the sample size

Confidence interval

The best point of estimate for the true mean is:

$\hat \mu = \bar X = 2.55$

The confidence interval for the true mean is given by:

$\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (1)

The Confidence level given is 0.95 or 95%, th significance would be $\alpha=0.05$ and $\alpha/2 =0.025$ . If we look in the normal distribution a quantile that accumulates 0.025 of the area on each tail we got $z_{\alpha/2}=1.96$

Replacing we got:

$2.55-1.96\frac{12}{\sqrt{76}}=-0.148$

$2.55+1.96\frac{12}{\sqrt{76}}=5.248$

Since the time can't be negative a good approximation for the confidence interval would be (0,5.248) minutes. The interval are tellling to us that at 95% of confidence the average late time is lower than 5.248 minutes.

7 0

3 years ago