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Sati [7]
1 year ago
8

Write a cosine function that Has a midline of 2 an amplitude of 3 and a period of 7pi/4

Mathematics
1 answer:
Alexxx [7]1 year ago
5 0

Given:

Amplitude of cosine function, A=3.

Period, T=7π/4.

Midline, D=2.

The time period can be expressed as:

T=\frac{2\pi}{B}

Put T=7π/4 to find the value of B.

\begin{gathered} \frac{7\pi}{4}=\frac{2\pi}{B} \\ B=\frac{4\times2}{7} \\ =\frac{8}{7} \end{gathered}

The general cosine function can be expressed as,

f(x)=A\cos (Bx)+D

Substitute B=8/7, A=3 and D=2 in above equation.

f(x)=3\cos (\frac{8}{7}x)+2

Therefore, the cosine function is,

f(x)=3\cos (\frac{8}{7}x)+2

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Answer:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

This is solving for x

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Multiply both sides by -1

and the answer is  

y=−24−4x

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Point B is on a line that has a slope of 2. Which of these could be the coordinates of another point on the line?
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