Add the two x’s to get -.3 then divided that by 6.3 and get -21
The answer to this is 394.83.
Answer:
8 3/4 cubic or 8.75
Step-by-step explanation:
To find volume it’s
Length * width * height
Answer:

Step-by-step explanation:

Answer:

And the best answer on this case would be:
b) m = 4.635
Step-by-step explanation:
Let X the random variable of interest and we know that the confidence interval for the population mean
is given by this formula:

The confidence level on this case is 0.9 and the significance 
The confidence interval calculated on this case is 
The margin of error for this confidence interval is given by:

Since the confidence interval is symmetrical we can estimate the margin of error with the following formula:

Where Upper and Lower represent the bounds for the confidence interval calculated and replacing we got:

And the best answer on this case would be:
b) m = 4.635