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valentinak56 [21]
3 years ago
8

On two examinations, you have grades of 87 and 86. There is an optional final examination, which counts as one grade. You decide

to take the final in order to get a course grade of Ameaning a final average of at least 90 a. What must you get on the final to in the course? b. By taking the final, if you do poorly, you might risk the B that you have in the course based on the first two exam grades. your final average is less than , you lose your B in the courseDescribe the grades on the final that will cause this to happen
Mathematics
1 answer:
noname [10]3 years ago
3 0

Step-by-step explanation:

We have

87+86+x

T is the total scores

n is number of tests done = 3

T/n is greater than or equal to 90

To get minimum test

T/n = 90

T = 90*n

= 90n

We solve for x

Remember n = 3

90x3 = 270

270 = 87+86+x

270 = 173+x

X = 270-173

X = 97

1.

X = 97

2.

You didn't add a value in your part b question. I used 80 though.

T/n < 80

T<80n

80x3= 240

T<240

87+86+x<240

X<240-173

X<67

X has to be less than 67 so we conclude that if x <=67 b grade will be lost.

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Answer:

\Large \boxed{ -x+65}

Step-by-step explanation:

Two points are (0, 65) and (10, 55)

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Use slope-intercept form

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Kruka [31]

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now 2nd equation

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x = -2

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6 0
3 years ago
Find the mean of the data set: 9 4 7 3 10 9
almond37 [142]
To find the mean, add up at the numbers and divide by the number of numbers in the set (6)

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Read 2 more answers
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NemiM [27]
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7 0
3 years ago
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denis23 [38]
Let T = cost of a taco
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2T + S + .08(2T + S) + 3 = 13.80
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Check: 2T + S + .08(2T + S) + 3 = 13.80
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13.80 = 13.80
Answer checks as correct
8 0
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