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Mrac [35]
3 years ago
6

An ice cream parlor has 6 different flavors. they have 4 toppings and 2 types of cones. how many possible ice cream combinations

are there? answer
Mathematics
1 answer:
vlabodo [156]3 years ago
3 0
6*4=24*2=48 combinations
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In a certain month, Mason spent 1/6 of his salary in the first three days and $800 in the following ten days and after that he w
Nesterboy [21]
<h3>Answer:   $2400</h3>

========================================================

Explanation:

x = Mason's salary in dollars for that month

x/6 = one-sixth of his salary

x/6+800 = total amount spent (the x/6 dollars and $800 combined)

In total, he spent half his salary. This means he spent x/2 dollars for the month overall.

Set the two items equal to one another. Solve for x.

x/6 + 800 = x/2

6(x/6 + 800) = 6*(x/2) ... see note at the bottom of the page

x+4800 = 3x

4800 = 3x-x

4800 = 2x

2x = 4800

x = 4800/2

x = 2400

His monthly salary is $2400

1/6 of this is (1/6)*2400 = 2400/6 = 400 dollars. Add on the $800 he also spent to get a total of 400+800 = 1200 dollars spent, which is exactly one half of the $2400. The answer is confirmed.

-------

Note: I multiplied both sides by 6 to clear out the fractions. The value 6 is the LCD in this case.

7 0
2 years ago
HELP FOR BRAINLIEST &amp; 50<br> please
Ganezh [65]

Answer:

pd 6 13.25

Step-by-step explanation:

4 0
2 years ago
I NEED HELP ASAP!! will be willing to mark you brainliest!
Softa [21]

Answer:

8/75

Step-by-step explanation:

5 0
3 years ago
When a scientist conducted a genetics experiments with peas, one sample of offspring consisted of 943 peas, with 717 of them hav
pshichka [43]

Using the normal approximation to the binomial distribution, it is found that:

a) 0.242 = 24.2% probability of getting 717 or more peas with red flowers.

b) Since Z < 2, 717 peas with red flowers is not significantly high.

c) Since 717 peas with red flowers is not a significantly high result, we cannot conclude that the scientist's assumption is wrong.

For each pea, there are only two possible outcomes. Either they have a red flower, or they do not. The probability of a pea having a red flower is independent of any other pea, which means that the binomial distribution is used to solve this question.

Binomial distribution:

Probability of x successes on n trials, with p probability.

Normal distribution:

In a normal distribution with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

  • It measures how many standard deviations the measure is from the mean.  
  • After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.
  • If Z > 2, the result is considered <u>significantly high</u>.

If np \geq 10 and n(1-p) \geq 10, the binomial distribution can be approximated to the normal with:

\mu = np

\sigma = \sqrt{np(1-p)}

In this problem:

  • 943 peas, thus, n = 943
  • 3/4 probability of being red, thus p = \frac{3}{4} = 0.75.

Applying the approximation:

\mu = np = 943(0.75) = 707.25

\sigma = \sqrt{np(1-p)} = \sqrt{943(0.75)(0.25)} = 13.297

Item a:

Using continuity correction, this probability is P(X \geq 717 - 0.5) = P(X \geq 716.5), which is <u>1 subtracted by the p-value of Z when X = 716.5</u>.

Then:

Z = \frac{X - \mu}{\sigma}

Z = \frac{716.5 - 707.25}{13.297}

Z = 0.7

Z = 0.7 has a p-value of 0.758.

1 - 0.758 = 0.242

0.242 = 24.2% probability of getting 717 or more peas with red flowers.

Item b:

Since Z < 2, 717 peas with red flowers is not significantly high.

Item c:

Since 717 peas with red flowers is not a significantly high result, we cannot conclude that the scientist's assumption is wrong.

A similar problem is given at brainly.com/question/25212369

6 0
2 years ago
<img src="https://tex.z-dn.net/?f=y%20%3D%204%20%28%5Cfrac%7B1%7D%7B2%7D%29%5E%7B2%7D%20" id="TexFormula1" title="y = 4 (\frac{1
poizon [28]
Solve using PEMDAS (Parenthesis, Exponent, Multiply, Divide, Add, Subtract) to find Y

Solve Exponent first
1/2^2 = 0.25

Multiply
4 x 0.25 = 1
y = 1

3 0
2 years ago
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