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kotykmax [81]
3 years ago
11

30% of the empty at a company picnic are a hot dog for lunch. If 18 employees are a hot dog, how many people were at the picnic

Mathematics
1 answer:
Keith_Richards [23]3 years ago
3 0

I believe the answer would be 600 people. I'm not sure how else to do this besides dividing 18 by .03 (30%) so then you should get 600.

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weeeeeb [17]

i y vino the answer is 60° i hope so

8 0
3 years ago
jordan has 90 photos.explain three ways he can arrange the photos in his album so he has the same number of photos on each page
erik [133]

Answer:

Divide the number of pages in the album by the 90 photos

Place one photo on a page at a time then start over when he reaches the end of the album and continue to repeat until all photos are gone

Just have one page of photos




Step-by-step explanation:


6 0
3 years ago
Read 2 more answers
(a) The probability that an automobile being filled with gasoline will also need an oil change is 0.35; the probability that it
cricket20 [7]

Answer:

0.714 ; 0.556 ; (A1 n A2 n A3) = 0

Step-by-step explanation:

Given that :

P(oil) = 0.35

P(filter) = 0.45

P(oil n filter) = 0.25

1)

P(filter | Oil) = P(oil n filter) / P(oil)

P(filter | Oil) = 0.25 / 0.35 = 0.714

11)

P(Oil | filter) = P(oil n filter) / P(filter)

P(Oil | filter ) = 0.25 / 0.45 = 0.556

Number of red aces = 2

Queen or king = 4 + 4 = 8

Number on card greater than 3 and less than 8 = {4,5,6,7} = 4 card ; for 4 suits = 4 * 4 = 16

Total number of cards in deck = 52

Choosing without replacement :

Hence,

A1 = 2 / 52

A2 = 8 / 51

A3 = 16 / 50

(A1 n A2 n A3) ;this means card common to all three events.

However, (A1 n A2 n A3) = 0 because ;

1.) No red ace card is greater than 3 and less than 8.

11.) An ace card can neither be a king nor a queen

3 0
3 years ago
Assume that you assign the following subjective probabilities for your final grade in your econometrics course (the standard GPA
rodikova [14]

Answer:

E(X) = 4*0.2 +3*0.5+ 2*0.2 +1*0.8+ 0*0.02= 2.78

So then the best answer for this case would be:

C. 2.78

Step-by-step explanation:

For this case we have the following probabability distribution function given:

Score         P(X)

A= 4.0       0.2

B= 3.0       0.5

C= 2.0       0.2

D= 1.0        0.08

F= 0.0       0.02

______________

Total          1.00

The expected value of a random variable X is the n-th moment about zero of a probability density function f(x) if X is continuous, or the weighted average for a discrete probability distribution, if X is discrete.

If we use the definition of expected value given by:

E(X) = \sum_{i=1}^n X_i P(X_I)

And if we replace the values that we have we got:

E(X) = 4*0.2 +3*0.5+ 2*0.2 +1*0.8+ 0*0.02= 2.78

So then the best answer for this case would be:

C. 2.78

3 0
3 years ago
Please help me asap! sorry this si english =(
Ilia_Sergeevich [38]
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7 0
3 years ago
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