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tiny-mole [99]
3 years ago
8

Graph the function f(x)=1/2 sqrt(x+1)

Mathematics
1 answer:
goldenfox [79]3 years ago
3 0

The function is defined only if x+1 \geq 0 \iff x \geq -1. So, the leftmost point is x=-1, and we have


f(-1)=\frac{1}{2}sqrt(-1+1) = 0


So, the first point is (-1,0)


The three additional points seem arbitrary, so let's choose x=0,1,2. We have:


f(0)=\frac{1}{2}sqrt(0+1) = \frac{1}{2}


So, the second point is (0,\frac{1}{2})


f(1)=\frac{1}{2}sqrt(1+1) = \frac{\sqrt{2}}{2}


So, the third point is (1,\frac{\sqrt{2}}{2})


f(2)=\frac{1}{2}sqrt(2+1) = \frac{\sqrt{3}}{2}


So, the fourth point is (2,\frac{\sqrt{3}}{2})

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assuming that the teacher wanted you to make it equal to zero do
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remember if we can do
xy=0 then assume x and y=0

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use quadratice formula which is

if you have
ax^2+bx+c=0 then
x=\frac{-b+/- \sqrt{b^{2}-4ac} }{2a}

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c=18

x=\frac{-7+/- \sqrt{7^{2}-4(1)(18)} }{2(1)}
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