F(x) is continuous for all x.
Pick a point and show that f(x) is either negative or positive. Pick another point and show that f(x) is negative, if positive, or positive, if negative.
At x = 30, f(30) - 1000 = 900 + 10sin(30) - 1000 ≤ 0
Now, show at another point f(x) - 1000 is positive, and hence, there would be root between 30 and such point.
Let's pick 40.
At x = 40, f(40) - 1000 = 1600 + 10sin(40) - 1000 ≥ 0
Since f(x) - 1000 is continuous, there lies a root between 30 and 40, and hence, 30 ≤ c ≤ 40
Answer:
Step-by-step explanation:
I'm pretty sure its lease penalty
Answer:
The distance should be 
Step-by-step explanation:
Distance formula
Answer:
n = 4
Step-by-step explanation:
Use the explicit formula of a arthmetic sequence: an = a1 + d(n - 1)
a1 = -70
d = -10
an = -100
Do all of the steps and plug all the numbers with the formula.
So -100 = -70 - 10(n - 1)
-100 = -70 - 10n + 10
-100 = -60 - 10n
-100 + 60 = -40
-40 = -10n
-40/-10n = -10n/10
n = 4
So the final answer is n = 4. Just follow all of the steps and you will understand how I got my answer. Hope it helped!
