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Marrrta [24]
3 years ago
11

1.18. A fish tank has a base, B, with an area, in square inches, modeled by B(x) = 2x + 6x + 4.

Mathematics
1 answer:
Alekssandra [29.7K]3 years ago
4 0

Answer:

The volume of fish tank is V(x)=2x^3+12x^2+22x+12

Step-by-step explanation:

Area of Base of fish tank = Length \times Breadth

We are given that A fish tank has a base, B, with an area, in square inches, modeled byB(x) = 2x^2 + 6x + 4.

So,  Length \times Breadth =2x^2 + 6x + 4.

Height of tank = x+3

Volume of tank = Length \times Breadth \times Height

So, Volume of tank =(2x^2 + 6x + 4)(x+3)

Volume of Tank =2x^3+6x^2+4x+6x^2+18x+12=2x^3+12x^2+22x+12

Hence The volume of fish tank is V(x)=2x^3+12x^2+22x+12

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F(t) = -2t + 5 f() = 13
fomenos

Answer:

I don't know what the question is but...

Step-by-step explanation:

-2t+5-13= -2t-8

-2t+5+13=-2t+18

-2t+5*13= -2t+65

-2t+5/13= -26t-5/13

8 0
3 years ago
Read 2 more answers
The answer for this problem
ElenaW [278]

Only the 3. option can be used. All other values dont fit


4 0
3 years ago
Find the surface area of the prism or pyramid. Round to the nearest hundredth if necessary.
son4ous [18]

Answer: 345.4

Step-by-step explanation:

SA=2πr^2+2πrh

SA=2(3.14)(5)^2+2(3.14)(5)(6)

SA=2(3.14)(25)+2(3.14)(30)

SA=2(78.5)+2(94.2)

SA=157+188.4

SA=345.4

4 0
3 years ago
How do I find the volume of this sphere while using 3.14
yawa3891 [41]
Vsphere=(4/3)pir³

d/2=r
d=6.2
6.2/2=r=3.1

vsphere=(4/3)pi3.1³
vsphere=(4/3)pi29.791
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answer is 124.72498666666666666666666666667 cubic feet
or rounded to neares whole, 125 square feet
7 0
3 years ago
Please Help!!<br> f(x) = square root of x plus 7 ; g(x) = 8x -11 <br> Find f(g(x))
Sonja [21]

I'm not sure if you mean ( \sqrt{x + 7} ) or ( \sqrt{x}  + 7 ) I solved it both ways .

f(x) =  \sqrt{x + 7}  \\  \\ f( \: g(x) \: ) =  \sqrt{(8x - 11)+ 7}  \\  =  \sqrt{8x - 11 + 7}  \\   =  \sqrt{8x - 4}  \\  = 2 \sqrt{2x - 1}

____o_____o______

f(x) =  \sqrt{x}  + 7 \\  \\ f( \: g(x) \: ) =  \sqrt{(8x - 11)}  + 7 \\  =  \sqrt{8x - 11}   + 7\\

I hope I helped you^_^

8 0
3 years ago
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