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Marrrta [24]
3 years ago
11

1.18. A fish tank has a base, B, with an area, in square inches, modeled by B(x) = 2x + 6x + 4.

Mathematics
1 answer:
Alekssandra [29.7K]3 years ago
4 0

Answer:

The volume of fish tank is V(x)=2x^3+12x^2+22x+12

Step-by-step explanation:

Area of Base of fish tank = Length \times Breadth

We are given that A fish tank has a base, B, with an area, in square inches, modeled byB(x) = 2x^2 + 6x + 4.

So,  Length \times Breadth =2x^2 + 6x + 4.

Height of tank = x+3

Volume of tank = Length \times Breadth \times Height

So, Volume of tank =(2x^2 + 6x + 4)(x+3)

Volume of Tank =2x^3+6x^2+4x+6x^2+18x+12=2x^3+12x^2+22x+12

Hence The volume of fish tank is V(x)=2x^3+12x^2+22x+12

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6, 12, 18, 24,...

First of all we have to find the common difference. The common difference is the difference between consecutive terms of an arithmetic sequence.

Here,

d=a_2-a_1 = 12-6 = 6\\d=a_3-a_2= 18-12 = 6

The general form for arithmetic sequence is:

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Putting the values for a_1 and d

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The equation is: a_n=6n

Keywords: Arithmetic sequence, Common Difference

Learn more about arithmetic sequence at:

  • brainly.com/question/10703930
  • brainly.com/question/10772025

#LearnwithBrainly

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