Use the root test to find the nature of the series : i need solutions details please

PLEASE HELP ASAP!!! I NEED CORRECT ANSWERS ONLY PLEASE!!!

Mila [183]

Answer:

$m\angle H = 44.4\°$ .

Step-by-step explanation:

Given:

In Right Angle Triangle GIH

∠ I = 90°

GI = 7 ....Side opposite to angle H

GH = 10 .... Hypotenuse

To Find:

m∠H = ?

Solution:

In Right Angle Triangle ABC ,Sine Identity,

$sin \ H = \frac{Oppsite\ side\ to\ \angle H}{Hypotenuse}$

Substituting the values we get;

$sin\ H = \frac{7}{10} = 0.7$

Now taking $sin^{-1}$ we get;

$\angle H = sin^{-1}\ 0.7 = 44.427$

rounding to nearest tenth we get.

$m\angle H = 44.4\°$ .

Hence $m\angle H = 44.4\°$ .

6 0

3 years ago

The table shows sales data for two sales people at a car dealership. Use rates to compare the performances of the salespeople.

Gennadij [26K]

Answer:

sorry to my answer i need a point and i ask a question Sorry :(

8 0

3 years ago

Read 2 more answers

Brainly to whomever somehow solves for x. I WILL REPORT SCAMS AND UNHELPFUL "WHAT?" ANSWERS.

cestrela7 [59]

Answer:

$x=\frac{33}{7}$

Step-by-step explanation:

Since ED is parallel to CA, the two triangles in the figure share all 3 angles and therefore must be similar. By definition, the corresponding sides of similar polygons are in a constant proportion.

Therefore, we have:

$\frac{11}{11+x}=\frac{14}{20},\\14(11+x)=20\cdot 11,\\11+x=\frac{20\cdot 11}{14},\\x=\frac{110}{7}-11=\boxed{\frac{33}{7}}$

3 0

3 years ago

Betsy participates in a scavenger hunt that requires her to retrieve items from 4 locations. The locations are on a map with the

Andreas93 [3]

Answer:

240 yd

Step-by-step explanation:

Let A, B, C, and D represent location 1, location 2, location 3, and location 4 respectively.

Consider the figure in the attached file.

We need to find the total distance traveled by Betsy.

The distance covered by Betsy is

length of segment AB length of segment BC length of segment CD length of segment DA.

To find the distance AB, we need to find the distance from A to B on y-axis.

So, length of segment AB units

To find the distance BC, we need to find the distance from B to C on x-axis.

So, length of segment BC units

To find the distance CD, we need to find the distance from C to D on y-axis.

So, length of segment CD units

To find the distance DA, we need to find the distance from D to A on x-axis.

So, length of segment DA units

Hence, the total distance covered is units

It is given that 1 unit equals 10 yd, so distance traveled by Besty is yd

3 0

3 years ago

Please help me! I'm stuck and really confused, thank you so much!

Kryger [21]

Answer:

(a) $5 * (2x - 1) = 10x - 5$

(b) $6 * x = x + 2x + 3x$

(c) $\frac{1}{2}(x - 6) = \frac{1}{2}x - 3$

(d) $y(3x + 4z) = 3xy + 4yz$

(e) $z(2xy - 3y + 4x) = 2xyz - 3yz + 4xz$

Step-by-step explanation:

Solving (a):

Given

$10x - 5$

Required

Express as a product

Express 10x as 5 * 2x

$10x - 5 = 5 * 2x - 5$

Apply distributive property

$10x - 5 = 5(2x - 1)$

$10x - 5 = 5 * (2x - 1)$

So:

$5 * (2x - 1) = 10x - 5$

Solving (b):

Given

$x + 2x + 3x$

Required

Express as a product

Express 2x and 3x as 2 * x and 3 * x, respectively

$x + 2x + 3x = x + 2*x + 3*x$

Apply distributive property

$x + 2x + 3x = x(1 + 2 + 3)$

$x + 2x + 3x = x(6)$

$x + 2x + 3x = 6*x$

So:

$6 * x = x + 2x + 3x$

Solving (c):

Given

$\frac{1}{2}(x - 6)$

Required

Express as a sum/difference

Apply distributive property

$\frac{1}{2}(x - 6) = \frac{1}{2}x - \frac{1}{2}*6$

$\frac{1}{2}(x - 6) = \frac{1}{2}x - \frac{6}{2}$

$\frac{1}{2}(x - 6) = \frac{1}{2}x - 3$

Solving (d):

Given

$y(3x + 4z)$

Required

Express as a sum/difference

Apply distributive property

$y(3x + 4z) = 3x * y + 4z * y$

$y(3x + 4z) = 3xy + 4yz$

Solving (e):

Given

$2xyz - 3yz + 4xz$

Required

Express as a product

Factorize

$2xyz - 3yz + 4xz = 2xy * z - 3y * z + 4x * z$

Apply distributive property

$2xyz - 3yz + 4xz = z(2xy - 3y + 4x)$

So:

$z(2xy - 3y + 4x) = 2xyz - 3yz + 4xz$

8 0

3 years ago