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dalvyx [7]
3 years ago
6

What is the relationship between a rotation and a rigid motion?

Mathematics
1 answer:
Papessa [141]3 years ago
5 0
A rotation is a rigid motion
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Hi, please answer with proof how you got this answer.
Orlov [11]

Answer: you would do lxw and W=5 and L=2 so what u would do it 5x2=10 so your answer is 10

5 0
3 years ago
Read 2 more answers
What are the following values from least to greatest 0 6 1/2 -1 9 can you help me pleaseeee​
alisha [4.7K]
-1, 0, 1/2, 6, 9 hope that helps
7 0
2 years ago
A projectile is fired with muzzle speed 250 m/s and an angle of elevation 45° from a position 30 m above ground level. Where doe
qaws [65]

The projectile's horizontal and vertical positions at time t are given by

x=\left(250\dfrac{\rm m}{\rm s}\right)\cos45^\circ\,t

y=30\,\mathrm m+\left(250\dfrac{\rm m}{\rm s}\right)\sin45^\circ\,t-\dfrac g2t^2

where g=9.8\dfrac{\rm m}{\mathrm s^2}. Solve y=0 for the time t it takes for the projectile to reach the ground:

30+\dfrac{250}{\sqrt2}t-4.9t^2=0\implies t\approx36.2458\,\mathrm s

In this time, the projectile will have traveled horizontally a distance of

x=\dfrac{250\frac{\rm m}{\rm s}}{\sqrt2}(36.2458\,\mathrm s)\approx6400\,\mathrm m

The projectile's horizontal and vertical velocities are given by

v_x=\left(250\dfrac{\rm m}{\rm s}\right)\cos45^\circ

v_y=\left(250\dfrac{\rm m}{\rm s}\right)\sin45^\circ-gt

At the time the projectile hits the ground, its velocity vector has horizontal component approx. 176.77 m/s and vertical component approx. -178.43 m/s, which corresponds to a speed of about \sqrt{176.77^2+(-178.43)^2}\dfrac{\rm m}{\rm s}\approx250\dfrac{\rm m}{\rm s}.

7 0
3 years ago
Which of the following ratios is equivalent to 49:35?
Arte-miy333 [17]

The best way to find it is to reduce each ratio you work with to its
lowest terms,and see which ones are equal. To reduce a ratio to its
lowest terms, divide each number by their greatest common factor.

First, the one that you're trying to match:  <u>49:35</u> .
The greatest common factor of 49 and 35 is 7 .
Divide each number by 7 . . .  <em>7:5</em> . . . <u>that's</u> what you have to match.

<u>7:4</u>
Their greatest common factor is ' 1 '.
No help at all, and this one is not it.

<u>14:25</u>
Again, their greatest common factor is '1 '.
No help at all, and this one is not it.

<u>21:15</u>
Their greatest common factor is ' 3 '.
Divide both numbers by 3 . . . <em>7:5 </em>.
That's it !
8 0
3 years ago
Read 2 more answers
Andy is collecting pocket change for a fundraiser. he begins with 102 coins in the cup, and their monetary value is $17.10. if h
Ira Lisetskai [31]

If Andy has 102 coins mixed with dimes and quarters and monetary value of $17.10 then he has 56 dimes and 42 quarters.

Given number of coins Andy has is 102 and montary value of all coins is $17.10.

We have to determine number of dimes and quarters.

1 dime=$0.10

1 quarter=$0.25

Suppose the number of dimes be x and number of quarters be y.

The equations are:

0.10x+0.25y=17.10------------1

x+y=102-------------2

from equation 2, y=102-x

Put the value of y=102-x in equation 1

0.10x+0.25(102-x)=17.10

0.10x+25.5-0.25x=17.10

-0.15x=17.10-25.5

-0.15x=-8.4

x=8.4/0.15

x=56

Put the value of x in y=102-x

y=102-56

y=46

Hence Andy has 56 number of dimes and 46 quarters.

Learn more about equation at brainly.com/question/2972832

#SPJ4

5 0
2 years ago
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