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Dvinal [7]
4 years ago
12

A family decides to rent a boat for the day. The boats rental rate is $500 for the first two hours and $50 for each additional h

alf hour. Suppose the family budgeted $700 to rent the boat. What is the maximum number of additional fall hours for which they can’t rent the boat.
Mathematics
2 answers:
bixtya [17]4 years ago
3 0

its====the question for the answer is 550

UkoKoshka [18]4 years ago
3 0

Answer:

4 is the maximum number of additional half-hours  for which the family can rent the boat.

Step-by-step explanation:

Let us represent with x the number of additional half hours the boat can be rented.

Then notice the cost of renting the boat is modeled with the following expression:

500+50x

Since it is the sum of the $500  for the first two hours plus the cost of the additional half hours which is the product of the cost of a single half hour $50 times the number of additional half-hours.

The family budgeted $700 therefore to cover the bill, therefore we have the following inequality:

500+50x\le700

We solve it for x:

500-500+50x\le700\\[0.2in]50x\le200\\[0.2in]\displaystyle x\le\frac{200}{50}\\[0.2in]x\le4

Therefore, the family can rent the boat for a maximum number of 4 additional half hours

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IceJOKER [234]

Answer:

(12, -6)

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right  

Equality Properties

  • Multiplication Property of Equality
  • Division Property of Equality
  • Addition Property of Equality
  • Subtraction Property of Equality<u> </u>

<u>Algebra I</u>

  • Terms/Coefficients
  • Coordinates (x, y)
  • Solving systems of equations using substitution/elimination

Step-by-step explanation:

<u>Step 1: Define Systems</u>

-4x = y - 42

x = 18 + y

<u>Step 2: Solve for </u><em><u>y</u></em>

  1. Substitute in <em>x</em>:                                                                                                -4(18 + y) = y - 42
  2. Distribute -4:                                                                                                   -72 - 4y = y - 42
  3. [Addition Property of Equality] Add 4y on both sides:                                 -72 = 5y - 42
  4. [Addition Property of Equality] Add 42 on both sides:                                -30 = 5y
  5. [Division Property of Equality] Divide 5 on both sides:                               -6 = y
  6. Rewrite/Rearrange:                                                                                         y = -6

<u>Step 3: Solve for </u><em><u>x</u></em>

  1. Define original equation:                                                                               x = 18 + y
  2. Substitute in <em>y</em>:                                                                                                x = 18 - 6
  3. Subtract:                                                                                                           x = 12
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