Answer:
i dont know either sorryy
Answer:
H
Step-by-step explanation:
Let represent A and B
A and B is the sum of the first 50 consecutive multiples of 3 and 6, this is the same as a arithmetic sequence because arithmetic sequences have a common sum.
We can represent this as

where a^1 is the first term, d is the common sum, n is the number of multiples we adding.
The first term for both A and B respectively is 3 and 6.
Multiples implies that the Difference between A and B are 3 and 6 respectively. There are 50 consecutively. multiples.
Plug in the known parts for both.


We need to what percent of find 150% of 300.
B is twice as A, so this means that we need to multiply 2 by it original or 100% of it self.

So 200% is the answer.
Factor out the common term 6
6(x^2 - 11x + 24) = 0
Factor x^2 - 11x + 24
6(x - 8)(x - 3) = 0
Solve for x;
<u>x = 8,3</u>
2 in the first column and 5 in the second column
Solution :
y - 6 = -6 (x + 1)
y - 6 = -6x - 6
y = -6x - 6 + 6
y = -6x - 0
-6x - y - 0 = 0
y = -6x