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nalin [4]
3 years ago
13

Find the area of the following circles. a. A circle with a 8-inch radius b. A circle with a 10-kilometer radius c. A circle with

a 14-yard diameter d. A circle with a 22-centimeter diameter
Mathematics
2 answers:
natima [27]3 years ago
8 0

Answer: A. 201.14inches²

B. 314.28km²

C. 154yds²

D. 380cm²

Step-by-step explanation: the area of a circle is given by [pie] (22/7) multiplied by the square of the radius

Radius is half the diameter of the circle

Applying the formula 22/7 x r²:

A. 22/7 x 8² = 201.4inch²

B. 22/7 x 10² = 314.28km²

C. 22/7 x (14/2)² = 154yd²

D. 22/7 x (22/2)² = 380cm²

Kudos!

Thepotemich [5.8K]3 years ago
5 0
Area of a circle is A= \pi r^2.  The first one, a, the radius squared is 8*8=64.  So A=64 \pi.  If you multiply in pi as 3.14, you'll have 200.96 square inches.  The second one, b, the radius squared is 10*10=100.  So A=100 \pi square kilometers.  If you multiply in pi as 3.14 you'll have 314 square kilometers.  The third one, c, the radius squared is 14*14=196.  So A=196 \pi yd^2.  Or you could multiply in pi as 3.14 to get 615.44 yd squared.  For the last one, d, the radius squared is 22*22=484 cm.  Therefore, A=484 \pi cm^2, or multiply in 3.14 for pi to get 1519.76 cm squared.  There you go!
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FrozenT [24]

Answer:

48

Step-by-step explanation:

80% = .8

60 x .8 = 48

7 0
2 years ago
Read 2 more answers
Please answer my question bcz I can’t understand
RUDIKE [14]
Please send more context as of the "green numbers".

For the multiplication,

i 49 x 10 = 490
490 ÷ 10 = 49

ii 2.3 <span>÷ 10 = 0.23
0.23 x 10 = 2.3

iii 0.034 x 1000 = 34
34 </span><span>÷ 1000 = 0.034

iv 876 </span><span>÷ 100 = 8.76
8.76 x 100 = 876

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3 0
3 years ago
Please help if you can!!!!
storchak [24]

Answer:Well, I don't know what you got so I can't tell you if it is right.

If it works in both equations, it depends of whether your equations are set up correctly.

Here is how I would do this problem.

Let x = no. of hot dogs,y = number of sodas.

First equation is just about the number of things.

x + y = 15

Second equation is about the cost of things.

1.5 x + .75 y = 18

solve x+y = 15 for y  y = 15-x    substitute into second equation

1.5x + .75(15 - x) = 18    

You should get the correct answer for number of hot dogs if you solve this correctly.  Put your answer in the x + y =15 equation to get y.  Then put both x and y into the cost equation and check your answer.

Hope this helps.

Step-by-step explanation:

5 0
2 years ago
The measure of arc LK is?
Oksi-84 [34.3K]

Answer:

Step-by-step explanation:

Because MK is a diameter, then angle L is a right angle. We already know that the measure of angle K is 50, so the measure of angle M has to be 40 because of the triangle angle-sum theorem. The rule for inscribed angles and the arcs they cut off is that the angle is half the measure of its intercepted arc or, likewise, the arc is twice the measure of the angle that cuts it off. Since arc LK is across from angle M and is cut off by angle M, then arc LK is twice the measure of angle M, and is 80. That's the same reason why angle L is 90; arc MK is a semi-circle, with a degree measure of 180, and angle L is half of that.

Arc LK = 80

5 0
2 years ago
Expand the binomial<br> <img src="https://tex.z-dn.net/?f=%28x-%5Cfrac%7B2%7D%7B5%7D%29%5E%7B2%7D" id="TexFormula1" title="(x-\f
kkurt [141]

Answer:

(x- \frac{2}{5})^{2} = x^2 -\frac{4}{5}x + \frac{4}{25}

Step-by-step explanation:

You have two methods to expand this binomial.

Method 1  

If you have the expression:

(x- \frac{2}{5})^{2}

You can write the expression it in the following way:

(x-\frac{2}{5})^{2}=(x-\frac{2}{5})(x-\frac{2}{5})

Then, apply the distributive property:

(x-\frac{2}{5})(x-\frac{2}{5}) = x^2 -\frac{2}{5}x -\frac{2}{5}x+ (\frac{2}{5})\frac{2}{5}

Simplify the expression:

(x-\frac{2}{5})^2= x^2 -\frac{4}{5}x+ (\frac{4}{25})

---------------------------------------------------------------------------------------

Method 2

For any expression of the form:

(a-b)^2

Its expanded form will be:

(a-b)^2= a^2 -2ab + b^2

If

a = x

b =\frac{2}{5}

(x- \frac{2}{5})^{2} = x^2 - 2x\frac{2}{5} + (\frac{2}{5})^2

(x- \frac{2}{5})^{2} = x^2 -\frac{4}{5}x + \frac{4}{25}

3 0
3 years ago
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