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vampirchik [111]
4 years ago
7

Please help mee 3f + 4(2f - 5)

Mathematics
1 answer:
SpyIntel [72]4 years ago
8 0
11f-20
Explanation:
Use the distributive property to distribute the 4 to the values in the parenthesis
3f+8f-20

Then add your like terms to get your final answer
11f-20
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I’m pretty sure it’s 20%
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3 years ago
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The rod is made of A-36 steel and has a diameter of 0.22 in . If the rod is 4 ft long when the springs are compressed 0.7 in . a
ziro4ka [17]

The force in the rod when the temperature is 150 °F is 718.72 pounds-force.

<h3>How to determine the resulting the resulting force due to mechanical and thermal deformation</h3>

Let suppose that rod experiments a <em>quasi-static</em> deformation and that both springs have a <em>linear</em> behavior, that is, force (F), in pounds-force, is directly proportional to deformation. Then, the elongation of the rod due to <em>temperature</em> increase creates a <em>spring</em> deformation additional to that associated with <em>mechanical</em> contact.

Given simmetry considerations, we derive an expression for the <em>spring</em> force (F), in pounds-force,  as a sum of mechanical and thermal effects by principle of superposition:

F = k\cdot (\Delta x + 0.5\cdot \Delta l)   (1)

Where:

  • k - Spring constant, in pounds-force per inch.
  • \Delta x - Spring deformation, in inches.
  • \Delta l - Rod elongation, in inches.

The <em>rod</em> elongation is described by the following <em>thermal</em> dilatation formula:

\Delta l = \alpha \cdot L_{o}\cdot (T_{f}-T_{o})   (2)

Where:

  • \alpha - Coefficient of linear expansion, in \frac{1}{^{\circ}F}.
  • L_{o} - Initial length of the rod, in inches.
  • T_{o} - Initial temperature, in degrees Fahrenheit.
  • T_{f} - Final temperature, in degrees Fahrenheit.

If we know k = 1000\,\frac{lb}{in}, \Delta x = 0.7\,in, \alpha = 6.5\times 10^{-6}\,\frac{1}{^{\circ}F}, L_{o} = 48\,in, T_{o} = 30\,^{\circ}F and T_{f} = 150\,^{\circ}F, then the force in the rod at final temperature is:

F = \left(1000\,\frac{lb}{in} \right)\cdot \left[0.7\,in + 0.5\cdot\left(6.5\times 10^{-6}\,\frac{1}{^{\circ}F} \right)\cdot (48\,in)\cdot (150\,^{\circ}F-30\,^{\circ}F)\right]

F = 718.72\,lbf

The force in the rod when the temperature is 150 °F is 718.72 pounds-force. \blacksquare

To learn more on deformations, we kindly invite to check this verified question: brainly.com/question/13774755

3 0
3 years ago
PLZZZZ HELP!!!!!!!
grandymaker [24]

Hey User______________

Here is Your Answer...!!!

_____________________

LINES AND ANGLES

After observing we get as ..Going horizontal manner we get

1) Alternate Exterior Angles

2) None of these

3) Corresponding Angles

4)Alternate interior Angles

5) Corresponding Angles

3 0
3 years ago
Please help will give brainliestw
katovenus [111]

Answer:

6 square units

Step-by-step explanation:

In oder to do this, you need graph paper to make it easier and then mark your graph paper with the quadrants.

I got 3 unites for the height and 4 units for the base

4 x 3 = 12 square units

however the formula for a triangle is Ab/2

so divide 12/2 = 6

So its 6 square units

7 0
3 years ago
There are 6 and 2 over 3pounds of walnuts in a container, which will be divided equally into containers that hold 1 and 1 over 3
kodGreya [7K]
6 2/3 divided equally into containers holding 1 1/3 would be 1 1/3 + 1 1/3 + 1 1/3 + 1 1/3+ 1 1/3= 6 2/3. That would fill five containers with none leftover.
6 0
4 years ago
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