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DanielleElmas [232]

3 years ago

14

HELP BRAINLYNST ANSWER 40 points plz help help with the whole page and just to make sure do the answers answer cause I wanna kno

w if it is correct or not

1 answer:

madam [21]3 years ago

8 0

Answer:

11) .75 12) .65 13) .6 14) .4 15) a. .6 b. 4 16) .09 17) 9/100 18) .60 19) .20 10) .50

Step-by-step explanation:

Your'e welcome (;

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In a manufacturing process, a machine produces bolts that have an average length of 5 inches with a variance of .08. If we rando

xz_007 [3.2K]

Answer:

$\bar X \sim N(\mu , \frac{\sigma}{\sqrt{n}})$

And replacing:

$\mu_{\bar X}= 5$

And the deviation:

$\sigma_{\bar X}= \frac{0.283}{\sqrt{5}}= 0.126$

And the distribution is given:

$\bar X \sim N(\mu= 0.08, \sigma= 0.126)$

Step-by-step explanation:

For this case we have the following info given :

$\mu= 5. \sigma^2 =0.08$

And the deviation would be $\sigma = \sqrt{0.08}= 0.283$

For this case we select a sample size of n = 5 and the distirbution for the sample mean would be:

$\bar X \sim N(\mu , \frac{\sigma}{\sqrt{n}})$

And replacing:

$\mu_{\bar X}= 5$

And the deviation:

$\sigma_{\bar X}= \frac{0.283}{\sqrt{5}}= 0.126$

And the distribution is given:

$\bar X \sim N(\mu= 0.08, \sigma= 0.126)$

4 0

3 years ago

WILL MARK BRAINLIEST

UkoKoshka [18]

Answer:

The relationship is proportional ✧

5 0

3 years ago

A small military base housing 1,000 troops, each of whom is susceptible to a certain virus infection. Assuming that during the c

slava [35]

Answer:

$I=\frac{1000}{exp^{0,806725*t-0.6906755}+1}$

Step-by-step explanation:

The rate of infection is jointly proportional to the number of infected troopers and the number of non-infected ones. It can be expressed as follows:

$\frac{dI}{dt}=a*I*(1000-I)$

Rearranging and integrating

$\frac{dI}{dt}=a*I*(1000-I)\\\\\frac{dI}{I*(1000-I)}=a*dt\\\\\int\frac{dI}{I*(1000-I)}=\int a*dt\\\\-\frac{ln(1000/I-1)}{1000}+C=a*t$

At the initial breakout (t=0) there was one trooper infected (I=1)

$-\frac{ln(1000/1-1)}{1000}+C=0\\\\-0,006906755+C=0\\\\C=0,006906755$

In two days (t=2) there were 5 troopers infected

$-\frac{ln(1000/5-1)}{1000}+0,006906755=a*2\\\\-0,005293305+0,006906755=2*a\\a = 0,00161345 / 2 = 0,000806725$

Rearranging, we can model the number of infected troops (I) as

$-\frac{ln(1000/I-1)}{1000}+0,006906755=0,000806725*t\\\\-\frac{ln(1000/I-1)}{1000}=0,000806725*t-0,006906755\\-ln(1000/I-1)=0,806725*t-0.6906755\\\\\frac{1000}{I}-1=exp^{0,806725*t-0.6906755} \\\\\frac{1000}{I}=exp^{0,806725*t-0.6906755}+1\\\\I=\frac{1000}{exp^{0,806725*t-0.6906755}+1}$

6 0

3 years ago

Which logarithmic equation is equivalent to the exponential equation below?

Nataly_w [17]

With any equation you are allowed to take the logarithm of both sides so
5^c=125 now take the logarithm base 5 to both sides giving.
log5(5^c)=log5(125), using the rule log(a^b)=a*log(b) you get
c log5(5)=log5(125), since log5(5)=1
c=log5(125)

8 0

3 years ago

Read 2 more answers

How do I write the sum of 24+40 as a product of the greatest common factor and another sum

9966 [12]

Answer is 64 and a factor is 6/4 .

7 0

3 years ago