We know for our problem that the zeroes of our quadratic equation are
and
, which means that the solutions for our equation are
and
. We are going to use those solutions to express our quadratic equation in the form
; to do that we will use the <span>zero factor property in reverse:
</span>
<span>
</span>
<span>
Now, we can multiply the left sides of our equations:
</span>
<span>= </span>
=
=
Now that we have our quadratic in the form
, we can infer that
and
; therefore, we can conclude that
.
Ahh yes, negative exponents always give us a scare once and a while. All the negative means is to flip the position of its base. For instance, if x has a negative exponent and x in the denominator, all you would have to do is move x to the numerator with the same power (except it's no longer negative). Before we substitute x and all the other variables which the values given, let's eliminate the negatives first.
After flipping positions/eliminating the negative exponents it should look like this:
which simplifies to
now that everything is simplified, and all negative exponents are eliminated we can substitute x with 2, and y with (-4).
which simplifies to
Final Answer: - \frac{1}{32} [/tex]
The formula for the area of a triangle is (1/2)bh = A
when we plug in the numbers, we get (1/2)(3x-1)x = A
using the distributive property we get (1.5x - .5)x = A
Then its 1.5x^2 - .5x = A
then if we factor out 0.5x we get 0.5x(3x-1) = A
then with the zero product property, 0.5x can equal 0 and x would need to equal 0.
if 3x-1 = 0 , then 3x = 1 then x = 1/3. so our answer would be 1/3 I'm pretty sure because a length cannot be 0
Answer:
The answer is 4
Step-by-step explanation: I did the work and it works out like that I hope this helps
