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Lesechka [4]
3 years ago
14

20 points , will mark brainiest :)

Mathematics
2 answers:
tester [92]3 years ago
7 0

Answer:

1) 5417.412

2) 401.13

Step-by-step explanation:

1) $ 5 \times 10^3 + 4 \times 10^2 + 1 \times 10^1 + 7 \times 10^0 + 4 \times \frac{1}{10^1} + 1 \times \frac{1}{10^2} + 2  \times \frac{1}{10^3} $

$ 5 \times 10^3 = 5000 $\\ $  4 \times 10^2 = 400 $ \\ $   1 \times 10^1 = 10 $\\$  7 \times 10^0 = 7 \times 1 = 7 $\\$  4 \times \frac{1}{10^1} = 0.4 $\\$ 1 \times \frac{1}{10^2} = 0.01 $\\ $  2  \times \frac{1}{10^3} = 0.02 $ \\

Combining we have: $ 5000 + 400 + 10 + 7 + 0.4 + 0.01 + 0.002 = $ 5417.412.

2) $ 4 \times 10^2 + 1 \times 1\frac{1}{10^1} + 3 \times \frac{1}{10^2} $

$ 4 \times 10^2 = 400 $\\$ 1 \times 1\frac{1}{10^1} = 1 \times \frac{11}{10} = 1 \times 1.1 = 1.1 $\\$ 3 \times \frac{1}{10^2} = 0.03 $

Combining we have: 400 + 1.1 + 0.03 = 401.13.

Hence, we have the answers.

son4ous [18]3 years ago
5 0

Answer:

A) The sum of given digits is 5417.412

B ) The sum of given digits is 401.103  

Step-by-step explanation:

Given sum of numbers as :

A ) 5 × 10³ + 4 × 10² + 1 × 10^{1} + 7 × 10^{0} + 4 × \frac{1} {10^{1}} + 1 × \frac{1}{10^{2}} + 2 × \frac{1}{10^{3}}

Or , 5000 + 400 + 10 + 7 × 1 + 0.4 + 0.01 + 0.002

or, ( 5400 + 10 + 7 ) + ( 0.4 + 0.01 + 0.002 )

Or, 5417 + 0.412

Or, 5417.412

Hence The sum of given digits is 5417.412

B ) 4 × 10² + 1 × ( 1 \frac{1} {10^{1}} ) + 3 × \frac{1}{10^{3}}

Or, 400 + 1 × (\frac{10+1}{10} ) + 0.003

Or, 400 + \frac{11}{10} + 0.003

Or, 400 + 1.1 + 0.003

Or, 401.103

Hence The sum of given digits is 401.103  

Answer

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Step-by-step explanation:

The volume of a cone is given by  V=\frac{1}{3}\pi r^2h

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<em>Where h is the height and r is the radius</em>

The first figure is a cone with height 6 and radius 5, we can put it into the formula and find the volume:

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5 0
4 years ago
Which two equations are true?(2×10−4)+(1.5×10−4)=3.5×10−4(3×10−5)+(2.2×10−5)=6.6×10−10 (6.3×10−1)−(2.1×10−1)=3×10−1(5.4×103)−(2.
tiny-mole [99]

let me edit your question as:

Which two equations are true?

<u>Eq1:</u>

(2×10−4)+(1.5×10−4)=3.5×10−4(3×10−5)+(2.2×10−5)

<u>Eq2:</u>

6.6×10−10(6.3×10−1)−(2.1×10−1)=3×10−1(5.4×103)−(2.7×103)

<u>Eq3:</u>

2.7×103(7.5×106)−(2.5×106)=5×100

Answer:

No one is true

Step-by-step explanation:

let's check each equation, if the values on both sides (left and right side) are equal then the equation is true otherwise false.

Using PEMDAS rule we are simplifying the equations as;

<u>Eq1:</u>

(2*10-4)+(1.5*10-4)=3.5*10-4(3*10-5)+(2.2*10-5)\\(16)+(11)=35-4(25)+(17)\\27=35-100+17\\27=-48\\

<u>Eq2:</u>

<u></u>6.6*10-10(6.3*10-1)-(2.1*10-1)=3*10-1(5.4*103)-(2.7*103)\\66-10(62)-(20)=30-1(556.2)-278.1\\66-620-20=30-556.2-278.1\\-574=-804.1<u></u>

<u>Eq3:</u>

2.7*103(7.5*106)-(2.5*106)=5*100\\221089.5-265=500\\220824.5=500\\

<u>we observed that none of the equation has two same values on both sides thus none of the three equations is true.</u>

<u>Also, no value of Eq1, Eq2 or Eq3 are same thus none of the equation is true</u>

8 0
3 years ago
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